Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 21 (Q.No. 16)
16.
The coordinates of two end-points A and B traverse line AB are XA = 1000.00 m, YA = 1000.00 m XB = 2000.00 m, YB = 1000.00 m The bearing of the line AB will be
Discussion:
5 comments Page 1 of 1.
Omar said:
4 years ago
Respectfully to everyone.
tan(90°) is N. D.
but tan^1(90°) = 89.36.
tan(90°) is N. D.
but tan^1(90°) = 89.36.
SanuT said:
5 years ago
Bearing of line AB = tan^-1 ( Xb-Xa /Yb-Ya).
= tan^-1 ( 2000-1000/ 1000-1000),
= tab^-1 (0),
= 90 degree.
= tan^-1 ( 2000-1000/ 1000-1000),
= tab^-1 (0),
= 90 degree.
Kishan datta said:
7 years ago
We have the formula to find out the angle by use of coordinate.
Bearing of line AB=tan-1 (Xb-Xa/Yb-ya).
= tan-1
(2000-1000/1000-1000)
= tan-1(1000/0).
= tan-1(infinity Or not define).
Now by use of trigonometric table find the angle which tan value should be infinity or not define
So the value is 90°.
ANS = 90°.
Bearing of line AB=tan-1 (Xb-Xa/Yb-ya).
= tan-1
(2000-1000/1000-1000)
= tan-1(1000/0).
= tan-1(infinity Or not define).
Now by use of trigonometric table find the angle which tan value should be infinity or not define
So the value is 90°.
ANS = 90°.
(1)
Smrithi said:
7 years ago
Line is horizontal in positive x direction.
(1)
Ajay kumar said:
9 years ago
Please explain it.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers