Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 22 (Q.No. 7)
7.
If a 30 m length can be taped with a precision of ± 0.01 m, then the standard error of measuring 1.08 km with the same precision will be
Discussion:
13 comments Page 1 of 2.
RAHUL said:
2 years ago
CORRECTED LENGTH = 1080 * (30+-.01)/30.
1080+-.36.
ERROR = MEASURED VALUE - TRUE VALUE.
=(1080+-36)-1080,
=±0.36.
1080+-.36.
ERROR = MEASURED VALUE - TRUE VALUE.
=(1080+-36)-1080,
=±0.36.
(1)
Apcivilian said:
3 years ago
I think C) 0.36 is the right answer.
(1)
Er. Satyam vishwakarma said:
3 years ago
Std error = +- &radic of no. Of measurement.
Std error = +- 6*e.
= +- 0.06m.
Std error = +- 6*e.
= +- 0.06m.
Raunak said:
3 years ago
Total error = +-(N x (error in the chain)^2).
N = no.of chain (L/30).
N = no.of chain (L/30).
Soumyajit Mandal said:
4 years ago
The law of probability states that error(e) is proportional to sqrt of that line(L).
Therefore,
e1/e2 = √L1/√L2.
=>0.01/e2 = √30/√1080.
=>e2 = 0.06.
Therefore,
e1/e2 = √L1/√L2.
=>0.01/e2 = √30/√1080.
=>e2 = 0.06.
(2)
Kalpana said:
5 years ago
The Correct answer is C.
Binay yadav said:
6 years ago
The Correct answer is C.
Arjun said:
6 years ago
Here, e is directly proportional to the √l.
Dhaval said:
6 years ago
I think C is the right answer.
Phani said:
7 years ago
Ans = 1.08 * 1000 * 0.01 ÷ 30,
= 0.36.
= 0.36.
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