Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 15 (Q.No. 33)
33.
A three-hinged symmetric parabolic arch is hinged at the springing and at the crown. The span and rise are 40 m and 10 m respectively. The left half of the arch is loaded with U.D.L. of 3 t/m. The horizontal thrust at the springings will be
Discussion:
4 comments Page 1 of 1.
Mahesh said:
8 years ago
The correct Ans is 30t.
w*l*l/16h = 2 * 40* 40/ (16*10)= 30t.
w*l*l/16h = 2 * 40* 40/ (16*10)= 30t.
(3)
Kashyap said:
2 years ago
3 * 40 * 40/16 * 10 = 30.
So, 30 is the correct answer.
So, 30 is the correct answer.
Goofy said:
6 years ago
30 t is the right answer.
Amith S said:
7 years ago
30t is the answer.
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