Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 18 (Q.No. 6)
6.
For the compound bar shown in the below figure, the ratio of stresses in the portions AB : BC : CD will be
Discussion:
4 comments Page 1 of 1.
Jaspal singh said:
1 month ago
Net forces will be
AB= F.
BC= F.
CD=2F.
SO stressed will be;
Sigma= Force/Area.
For AB stress = F/(π/4D²).
= 4F/πD².
SIMILARLY, for BC stress = 16F/πD^2.
And for CD stress = 8F/πD^2.
Now the ratio will be;
4F : 16F : 8F.
= 1 : 4 : 2.
Correct and C 1:4:2.
AB= F.
BC= F.
CD=2F.
SO stressed will be;
Sigma= Force/Area.
For AB stress = F/(π/4D²).
= 4F/πD².
SIMILARLY, for BC stress = 16F/πD^2.
And for CD stress = 8F/πD^2.
Now the ratio will be;
4F : 16F : 8F.
= 1 : 4 : 2.
Correct and C 1:4:2.
Ayanraaj said:
8 months ago
For Portion BC: Area is Minimum (D/2), so stress will be maximum.
Nivedha said:
1 year ago
Give an explanation for the answer.
Khalid said:
5 years ago
Please give explanation.
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