Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 25 (Q.No. 7)
7.
A body of mass 4 kg moving at 12 m/s collides with another body of mass 8 kg and adheres to it. The resultant velocity of the total mass in m/s will be
Discussion:
3 comments Page 1 of 1.
Sandy said:
3 years ago
m1v1 + m2v2 = (m1+m2)v,
V2 = 0.
V2 = 0.
Okunta said:
5 years ago
m1v1=m2v2.
Let M1 =4kg, V1=12m/s, M2=8kg, V2=?
4 * 12 = 8 * v2.
48 = 8v2.
V2 = 6m/s.
Let M1 =4kg, V1=12m/s, M2=8kg, V2=?
4 * 12 = 8 * v2.
48 = 8v2.
V2 = 6m/s.
Basu said:
7 years ago
Use m1v1=m2v2.
So, option C is the correct answer.
So, option C is the correct answer.
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