Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 1 (Q.No. 8)
8.
A concentrated load P is supported by the free end of a quadrantal ring AB whose end B is fixed. The ratio of the vertical to horizontal deflections of the end A, is
π
Discussion:
17 comments Page 1 of 2.
Kyra said:
5 years ago
Vertical deflection = V.D = π/4(wr^3/EI).
Horizontal Deflection = H.D = wr^3/2EI.
Their Ratio = V.D/H.D = π/2.
Horizontal Deflection = H.D = wr^3/2EI.
Their Ratio = V.D/H.D = π/2.
(10)
Pradip said:
5 years ago
ΔV = Vertical deflection (deflection in the direction of load P) at end A.
ΔH = Horizontal deflection of end A.
ΔH = Horizontal deflection of end A.
(1)
Sam said:
7 years ago
Vertical deflection = π/4(wr^3/EI).
OR
Horizontal deflection = (wr^3/2EI).
OR
Horizontal deflection = (wr^3/2EI).
Sukumar maloth said:
8 years ago
π/2 is the correct answer.
Ref : R.K Bansal Book.
Ref : R.K Bansal Book.
TuSHAR DAS said:
10 years ago
Please show the picture how the load is acting?
Pravin said:
5 years ago
Can somebody explain me the answer in detail?
(1)
Dinesh mandal said:
7 years ago
Please explain the Solution of the question.
(1)
Md. Easir Arafat said:
9 years ago
Please add the image to understand it.
Rakshan said:
7 years ago
Please explain the answer in detail.
Molla said:
7 years ago
Please explain, how it could be?
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