Civil Engineering - Theory of Structures - Discussion

29. 

A steel rod 1 metre long having square cross section is pulled under a tensile load of 8 tonnes. The extension in the rod was 1 mm only. If Esteel = 2 x 106 kg/cm2, the side of the rod, is

[A]. 1 cm
[B]. 1.5 cm
[C]. 2 cm
[D]. 2.5 cm

Answer: Option C

Explanation:

No answer description available for this question.

Sam said: (Oct 12, 2014)  
e = PL/AE.

Where,
e = extension in rod(0.1cm).
P = tensile load(8,000kg).
L = length of rod(100cm).
A = area of the x-section of rod(cm^2).
E = modulus of elasticity(2,000,000kg/cm^2).

Here x-section is a square so A=x^2.

Now x = square root(PL/eE).
x = [(8,000*100)/(.1*2,000,000)]^1/2.
x = 2cm.

Sks Pandey said: (Sep 9, 2016)  
Great @Sam nice explanation.

Deepak Singroul said: (Feb 19, 2017)  
e = PL/AE.
So
0.1= (8000 * 100)/(A * 2000000).
A = (8000 *100) / ( 0.1*2000000).
A = 4 squre cm.
So
Side = √4 = 2 cm. Ans.

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