### Discussion :: Theory of Structures - Section 1 (Q.No.29)

Sam said: (Oct 12, 2014) | |

e = PL/AE. Where, e = extension in rod(0.1cm). P = tensile load(8,000kg). L = length of rod(100cm). A = area of the x-section of rod(cm^2). E = modulus of elasticity(2,000,000kg/cm^2). Here x-section is a square so A=x^2. Now x = square root(PL/eE). x = [(8,000*100)/(.1*2,000,000)]^1/2. x = 2cm. |

Sks Pandey said: (Sep 9, 2016) | |

Great @Sam nice explanation. |

Deepak Singroul said: (Feb 19, 2017) | |

e = PL/AE. So 0.1= (8000 * 100)/(A * 2000000). A = (8000 *100) / ( 0.1*2000000). A = 4 squre cm. So Side = √4 = 2 cm. Ans. |

Abdullah said: (Apr 25, 2020) | |

Nice, Thanks @Deepak. |

#### Post your comments here:

Name *:

Email : (optional)

» Your comments will be displayed only after manual approval.