# Civil Engineering - Theory of Structures - Discussion

### Discussion :: Theory of Structures - Section 1 (Q.No.29)

29.

A steel rod 1 metre long having square cross section is pulled under a tensile load of 8 tonnes. The extension in the rod was 1 mm only. If Esteel = 2 x 106 kg/cm2, the side of the rod, is

 [A]. 1 cm [B]. 1.5 cm [C]. 2 cm [D]. 2.5 cm

Answer: Option C

Explanation:

No answer description available for this question.

 Sam said: (Oct 12, 2014) e = PL/AE. Where, e = extension in rod(0.1cm). P = tensile load(8,000kg). L = length of rod(100cm). A = area of the x-section of rod(cm^2). E = modulus of elasticity(2,000,000kg/cm^2). Here x-section is a square so A=x^2. Now x = square root(PL/eE). x = [(8,000*100)/(.1*2,000,000)]^1/2. x = 2cm.

 Sks Pandey said: (Sep 9, 2016) Great @Sam nice explanation.

 Deepak Singroul said: (Feb 19, 2017) e = PL/AE. So 0.1= (8000 * 100)/(A * 2000000). A = (8000 *100) / ( 0.1*2000000). A = 4 squre cm. So Side = √4 = 2 cm. Ans.

 Abdullah said: (Apr 25, 2020) Nice, Thanks @Deepak.

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