Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 4 (Q.No. 7)
7.
The equivalent length of a column of length L, having one end fixed and other end hinged, is
2L
L
Discussion:
1 comments Page 1 of 1.
Asaithambi said:
9 years ago
Both end hinged=l critical load= 3.14^2 * EI/L^2.
Both end fixed=l/2 critical load= 4*3.14^2 * EI/L^2.
One end fixed and other end hinged=l/(squ of 2) critical load= 2*3.14^2 * EI/L^2.
one end fixed and other end free=2l critical load= 3.14^2 * EI/4*L^2.
Both end hinged=l critical load= 3.14^2 * EI/L^2.
Both end hinged=l critical load= 3.14^2 * EI/L^2.
Both end fixed=l/2 critical load= 4*3.14^2 * EI/L^2.
One end fixed and other end hinged=l/(squ of 2) critical load= 2*3.14^2 * EI/L^2.
one end fixed and other end free=2l critical load= 3.14^2 * EI/4*L^2.
Both end hinged=l critical load= 3.14^2 * EI/L^2.
Both end hinged=l critical load= 3.14^2 * EI/L^2.
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