Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 2 (Q.No. 35)
35.
is the equation of Euler's crippling load, if
Discussion:
3 comments Page 1 of 1.
Vidya said:
6 years ago
Both ends fixed, Le = L\2.
Both ends hinged, Le = L.
One end fixed one end free, Le = 2L.
One end fixed one end hinged Le =L\√2.
Both ends hinged, Le = L.
One end fixed one end free, Le = 2L.
One end fixed one end hinged Le =L\√2.
(3)
Asay said:
7 years ago
Euler,s Crippling Load Eqn is;
P=(π)^2.EI/l^2.
If,
one end is fixed and other end is free
Then ,
l=2L, Put it into above equation.
P=(π)^2.EI/(2L)^2.
P=(π)^2.EI/4L^4.
So ,
C is the correct answer.
P=(π)^2.EI/l^2.
If,
one end is fixed and other end is free
Then ,
l=2L, Put it into above equation.
P=(π)^2.EI/(2L)^2.
P=(π)^2.EI/4L^4.
So ,
C is the correct answer.
(1)
Vardhan said:
7 years ago
Here, Both ends are fixed.
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