Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 2 (Q.No. 49)
49.
The ratio of the area of cross-section of a circular section to the area of its core, is
Discussion:
7 comments Page 1 of 1.
B.Singh said:
11 months ago
Dia of Core of circle = d/4.
Dia of Circle = d.
Area of Core/Area of Circle = 1/16 will get.
Dia of Circle = d.
Area of Core/Area of Circle = 1/16 will get.
Hon said:
3 years ago
Thanks @Aswathy.
Aswathy said:
3 years ago
Radius of circular section = r.
Radius of core section = r/4.
Area of circular section,A1 = πr^2.
Area of core section,A2 = π(r/4)^2 = (πr^2)/16.
Ratio ,A1/A2= πr^2/(πr^2/16) = 16.
Radius of core section = r/4.
Area of circular section,A1 = πr^2.
Area of core section,A2 = π(r/4)^2 = (πr^2)/16.
Ratio ,A1/A2= πr^2/(πr^2/16) = 16.
Gowthami. said:
4 years ago
Substitute the values in the area formulae.i.e., in CS Area d=2r and in core area d=r/2.
Shaswata said:
4 years ago
Circular = 1/16.
Damodar said:
6 years ago
What formula is used here? Please tell me.
Baloch said:
6 years ago
Use the formula = pi r^2.
The radius of core 1/4th of r, So, 4^2 = 16.
The radius of core 1/4th of r, So, 4^2 = 16.
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