### Discussion :: Theory of Structures - Section 1 (Q.No.40)

Rashmi said: (Aug 4, 2015) | |

8 = [64*P*(40^3)*8]/(80000*(4^4)). |

Achyut Paudel said: (Nov 5, 2015) | |

Can anyone solve this question with explanation? |

Ashish said: (May 30, 2016) | |

The formula is : (64 * p * (r^3) * n)/Nd4. |

Akit Pads said: (Sep 9, 2016) | |

@Ashish. By using this formula, I got an answer as 5N. Am I right? |

Snehal Wankhede said: (Sep 30, 2016) | |

For 1 clearance p = 5, 8 coil = 7 clearance, So, p total = 35. |

Aamir said: (Oct 24, 2017) | |

It contains 8 coils, and 1 coil contains 7 clearances there total clearance =56=56mm. |

Chulbul said: (Jan 27, 2018) | |

The question is asked to find the load. Not distance! p= (64W* R^3)/(C*d^4). We find out W, load for 1 clearance, between 2 coils. Between 2 coil, 1 clearance, load= 5N. Between 8 coil, 7 clearance, load= 5x7=35N. |

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