### Discussion :: Theory of Structures - Section 2 (Q.No.4)

Vishal Patil said: (Nov 11, 2015) | |

Explain it? |

Rohit Kumar said: (Jul 6, 2016) | |

By Torsion Equation: T/Ip = Fs/ymax = G$/L. Where T = Torsion Ip = Polar moment of inertia Ymax = Max distance from nuetral axis G = MODULUS of rigidity $ = Angle of twist in Radian Fs = Max shear force. Hence Fs/Ymax = G$/L So 50/100 = 0.8 * 100000/4000 (All diamension in MM) = 0.0025 Answer. |

Pinki said: (Jun 23, 2017) | |

According to me, the Right answer is 0.025. |

Manoj Paridwal said: (Sep 11, 2017) | |

Yes, @Pinki. The right answer is .025. |

Asay said: (Nov 21, 2017) | |

By TORSION EQUATION. T/I=Fs/Ymax=G$/L. ====> Fs/Ymax=G$/L. ====> $=Fs.L/G.Ymax ----> (1). Here, Fs=Maximum Shear Stress=50 N/mm2. And, Ymax=D/2=20/2=10cm=100mm And, G=0.8 x 105 N/mm2. $=Twisting Moment=? (Required) L=400cm=4000mm. Now , Putting the Values in eqn (1). $=50*4000/[0.8*100000*(100)]. $=0.025. |

Dheeraj said: (Feb 24, 2020) | |

The right answer is 0.025. |

B.Singh said: (Apr 4, 2022) | |

I think the answer is 0.025. |

Ramjan Ali said: (Oct 15, 2022) | |

We know, Shear stress/radius = G * angle of twist/L. So, 50/100=(0.8*10^5)*theta/4000. From the above equation after solving we will get the value of the angle of twist i.e. θ = 0.0025. I have converted the value of Dia to Radius (R=100mm). So, option (C) is correct. |

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