Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 3 (Q.No. 37)
37.
A shaft rotating N.R.M. under a torque T, transmits a power
Newton metres/sec Newton metres/min
Newton metres/min Newton metres/secDiscussion:
7 comments Page 1 of 1.
MCQ Poudel said:
7 months ago
P = T * w.
where T = Torque and w = angular velocity.
w = 2*π*f.
if we want to express in terms of rpm------> N.
N revolution in 1 minute,
N revolution in 60 sec.
N/60 revolution in 1 sec = f.
So, P = T * 2 * π *N/60 = T * N * π/30.
where T = Torque and w = angular velocity.
w = 2*π*f.
if we want to express in terms of rpm------> N.
N revolution in 1 minute,
N revolution in 60 sec.
N/60 revolution in 1 sec = f.
So, P = T * 2 * π *N/60 = T * N * π/30.
(1)
Khan baba said:
4 years ago
What is N. R. M? Please explain about it.
ABHI said:
7 years ago
POWER TRANSMITTED BY SHAFT = 2ΠNT/60 N-M/SEC.
BY SOLVING IT WE GET TΠN/30 N-M/SEC.
BY SOLVING IT WE GET TΠN/30 N-M/SEC.
(3)
PRIYA said:
8 years ago
But why taken 2π NT/60000.
Manju said:
8 years ago
P= 2πNT/60000 kw,
1kw=1000Nm/sec.
P=πNT/30.
1kw=1000Nm/sec.
P=πNT/30.
Murali said:
8 years ago
Yes, option D is correct.
Sheela said:
8 years ago
How A? I think D is the answer.
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