Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 3 (Q.No. 40)
40.
If D and d are external and internal diameters of a circular shaft respectively, its polar moment of inertia, is
Discussion:
4 comments Page 1 of 1.
Nabin said:
4 years ago
It's polar moment and not polar modulus because polar modulus Zp=J/τ.
Nabin said:
4 years ago
Polar modulus,Iz = Ix + Iy.
= (πD^4/64)+(πD^4/64),
= πD^4/32.
For the hollow section, you can take D and d.
= (πD^4/64)+(πD^4/64),
= πD^4/32.
For the hollow section, you can take D and d.
(1)
Sudas said:
5 years ago
Polar moment of inertia means Ix + Iy, so answer is correct.
Noora said:
6 years ago
The answer must be C.
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