# Civil Engineering - Theory of Structures - Discussion

### Discussion :: Theory of Structures - Section 1 (Q.No.38)

38.

The force in AD of the truss shown in given figure, is [A]. 4.0t compression [B]. 3.0t compression [C]. 0.5t compression [D]. 0.5t tension [E]. zero.

Explanation:

No answer description available for this question.

 Ddendu said: (Sep 5, 2013) Reactions are Va + Vb = 5t. Let length of each member be x. Moment atB = 4t * x - 5t * x + Va * 2x = 0. Therefore 1t = 2Va. Hence Va = 0.5t.

 Ishan said: (Mar 26, 2016) Hello Ddendu can you tell me, why the x is multiplied with 4t, as it is 2x distance away from B.

 Pradyumna Kumar Nayak said: (Apr 19, 2016) Hello, Ishan. It is a perpendicular distance of line of force and point B. So only x is multiplied.

 Pradyumna Kumar Nayak said: (Jul 29, 2016) Considering the joint A. As Va = 0.5 T upward. fac = 0 & fad = 0.5T compression.

 Michelle said: (Feb 22, 2017) Hi @Ddendu. How is EF=BC= X? Are all the members equal in a truss all the time?

 Manoj Paridwal said: (Sep 11, 2017) How it is compression. Show it will be .5 tension?

 Tapas said: (Feb 22, 2019) @Manoj Paridwal. When axial force moves towards the joint it is compression. As the reaction on the left side +ve so it is an upward reaction, so to balance it an equal downward force will be induced in the member AD. Hence both as the forces are moving towards the joint A hence the member AD is under compression.

 Adarsh said: (Jun 11, 2019) Very good, thanks @Dhendu.

 Pawan said: (Jun 16, 2019) Thanks @TAPAS.