Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 2 (Q.No. 3)
3.
The ratio of the length and diameter of a simply supported uniform circular beam which experiences maximum bending stress equal to tensile stress due to same load at its mid span, is
1.0
Discussion:
12 comments Page 1 of 2.
Rohit said:
9 years ago
Bending stress = M/Z.
Tensile stress = P/A.
From question,
Bending stress = Tensile stress.
i.e. M/Z = P/A.
M = PL/4.
Z = pi*d^3/32.
A = pi*d^2/4.
After putting these value, we get,
L/d = 1/2.
Tensile stress = P/A.
From question,
Bending stress = Tensile stress.
i.e. M/Z = P/A.
M = PL/4.
Z = pi*d^3/32.
A = pi*d^2/4.
After putting these value, we get,
L/d = 1/2.
(5)
Madan said:
3 years ago
For a simply supported beam with load at mid-span having length L .
Then Moment at the centre is (P/2*L/2)= PL/4.
Then Moment at the centre is (P/2*L/2)= PL/4.
Madan said:
3 years ago
M is a moment in simply supported beam by point load at mid-span having length L,
Then, M=PL/4.
Then, M=PL/4.
Er waqar said:
3 years ago
How it is possible that the span is half of its dia? Please explain me.
Saqib said:
6 years ago
Thanks for the explanation @Rohit.
Zia ur Rehman said:
6 years ago
Well explained, Thanks @Rohit.
Roy said:
7 years ago
Thanks for the answer @Rohit.
Saurav said:
4 years ago
How PL/4? Please explain.
Songeeta said:
9 years ago
Thank you @Rohit.
Amanjangra1997 said:
8 years ago
Thank you @Rohit.
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