Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 2 (Q.No. 39)
39.
The moment of inertia of a triangular section (height h, base b) about its base, is
Discussion:
2 comments Page 1 of 1.
Waseem Akhtar said:
5 years ago
I(triangle about centroid) = (b*h^3÷36).
I(triangle about base) = (b*h^3÷36) + Ar^2.
Where r is the perpendicular distance between the base and centroid (h/3 in a triangle),
I(triangle about base) = (b*h^3÷36) + (1/2*bh)*(h/3)^2,
Option C = (b*h^3÷12).
I(triangle about base) = (b*h^3÷36) + Ar^2.
Where r is the perpendicular distance between the base and centroid (h/3 in a triangle),
I(triangle about base) = (b*h^3÷36) + (1/2*bh)*(h/3)^2,
Option C = (b*h^3÷12).
Murali said:
8 years ago
Moi=(b*h^3÷36) is correct answer.
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