# Civil Engineering - Theory of Structures - Discussion

Discussion Forum : Theory of Structures - Section 2 (Q.No. 34)
34.
A simply supported beam which carries a uniformly distributed load has two equal overhangs. To have maximum B.M. produced in the beam least possible, the ratio of the length of the overhang to the total length of the beam, is
0.207
0.307
0.407
0.508
Explanation:
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Discussion:
7 comments Page 1 of 1.

Taha said:   6 years ago

Monika said:   6 years ago

Lufura said:   4 years ago
Give Explanation.

Akshi said:   4 years ago

Shubham said:   3 years ago
Max. BM = Min. BM.
If l= length of overhang.
L= length of ssb span.

wl2/8 - wl2/2 = wl2/2,
Solving this;
l/(L+2l) = 0.207.

Vinuthna said:   1 year ago
For overhanging beam on both sides;

If a = length of overhang.
L= length of the overall span.
l = length of span b/w supports = L-2a;
(+ve) Max BM = (-ve) Max BM.
Wl^2/8 - Wa^2/2 = Wa^2/2.
a = l/2*2=0.35 * l.
a = 0.35(L-2a).
a = 0.207L.
Ratio; a/L = 0.207.