Civil Engineering - Theory of Structures - Discussion

Thanks for explaining @Llokesh Sahu.

How the reaction at support b is negative? it would be positive.

Well said, Thanks, @Lokesh.

Thanks @Lokesh.

Really good explanation.

Let reaction loads are RA & RB @ point A & B.
RA+RB=wl/2.
To calculating we found RA= wl/6 & RB= -wl/3,
let take a section X-X @ a distance of x from A.
UVL will be @ X-X = wx/l,
& load on triangle ACX = wx2 /2l,
& find the SF @ X-X,
Fx= RA - load on triangle ACX,
Fx=( wl/6) - (wx2/2l) -------> (1)
Fx at A will be. X=0
Fx = wl/6
Fx at B will be. X=l
Fx=-wl/3.

Moment will be max, where Fx=0,
So, x= l/(3)1/2.
Now find the moment at X-X.

Mx = (RA*x) " (load on triangle ACX * x/3)load of the triangle will be act ta 1/3rd distance from A.
Mx= (wlx/6) " (wx3/6l)
Moment at x= l/(3)1/2
Mx= (wl*( l/(3)1/2)/6) - (w*( l/(3)1/2)3/6l)
Mx= wl2/9(3)1/2.

It is 2wl/9*√ 3.

According to me, It is wl^2÷9 √3EI.

It should be :(2wa^2)/(9 * square root of 3).