Civil Engineering - Theory of Structures - Discussion

Discussion Forum : Theory of Structures - Section 2 (Q.No. 32)
A bar l metre long and having its area of cross-section A, is subjected to a gradually applied tensile load W. The strain energy stored in the bar is
Answer: Option
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6 comments Page 1 of 1.

CHHAYA said:   7 years ago
It is 1/2*W*WL/AE.

Abhi said:   7 years ago
Deformation = WL/AE.

Strain Energy = 1/2 x W x Deformation.

Therefore W2L/2AE.

Amu bokato said:   5 years ago
Thanks @Abhi.

Lalit said:   4 years ago
Strain energy formula = {( sigma) ^2/(2E) }*Volume.
= {( sigma) ^2/(2E) }*A*L.
= {(W/A) ^2/(2E) }*A*E.
== {W^2L/(2AE) }.

Fahad said:   4 years ago
Thanks @Abhi @Lalit.

Shiv said:   9 months ago

Here, it will act like a self-weight of the bar so, the strain energy should be W^2L/6AE.

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