Discussion :: Theory of Structures - Section 2 (Q.No.40)
|Srinu said: (Dec 6, 2016)|
|Ch in vol= (p ÷ae)(1-2u)V.|
|Bhushan said: (Jan 5, 2018)|
|Here, Ch in volume=3 (Pl/E) (1-2m).|
|Shuva said: (Mar 22, 2018)|
|Yes, right agree @Srinu.|
|Ram said: (Mar 23, 2018)|
|Sourabh said: (Dec 13, 2018)|
|Please explain the answer in detail.|
|Imtiaz Hakim said: (Apr 1, 2020)|
hERE a steel bar 5m length and 50mm dia...then the original volume will be Pid2/4 multiply length = .01m3.
Now change in volume = 25000÷( .002 * .2 *10^6) multiply (1-2*.25).01 = 3.125cm3.
|Archana said: (Jul 17, 2021)|
|Can anyone explain the answer in detail?|
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