Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 1 (Q.No. 16)
16.
A load of 1960 N is raised at the end of a steel wire. The minimum diameter of the wire so that stress in the wire does not exceed 100 N/mm2 is :
Discussion:
13 comments Page 2 of 2.
K.vignesh. said:
7 years ago
Good explanation, Thanks @Jack.
Rajiv said:
5 years ago
P= 1960 N.
Stress= 100N/mm^2.
Formula(Sress= P/A).
100 = 1960/A.
A = 1960/100.
Where A=π/4d^2.
Then :- 22/7*4*d^2=196/10.
d^2= 28/22*196/10.
d= √25.
d= 5 =>Answer.
Stress= 100N/mm^2.
Formula(Sress= P/A).
100 = 1960/A.
A = 1960/100.
Where A=π/4d^2.
Then :- 22/7*4*d^2=196/10.
d^2= 28/22*196/10.
d= √25.
d= 5 =>Answer.
(1)
Mahesh said:
3 years ago
Stress = p/A.
Stress = 100N/mm2.
P = 1960N.
100 = 1960/A.
A = 196mm2.
3.14 * d2/4 = 196.
d = 5mm.
Stress = 100N/mm2.
P = 1960N.
100 = 1960/A.
A = 196mm2.
3.14 * d2/4 = 196.
d = 5mm.
(4)
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