# Civil Engineering - Theory of Structures - Discussion

Discussion Forum : Theory of Structures - Section 1 (Q.No. 16)
16.
A load of 1960 N is raised at the end of a steel wire. The minimum diameter of the wire so that stress in the wire does not exceed 100 N/mm2 is :
4.0 mm
4.5 mm
5.0 mm
5.5 mm
6.0 mm
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 1 of 2.

Mahesh said:   2 years ago
Stress = p/A.
Stress = 100N/mm2.
P = 1960N.
100 = 1960/A.
A = 196mm2.
3.14 * d2/4 = 196.
d = 5mm.
(3)

Rajiv said:   3 years ago
P= 1960 N.
Stress= 100N/mm^2.
Formula(Sress= P/A).

100 = 1960/A.
A = 1960/100.
Where A=π/4d^2.
Then :- 22/7*4*d^2=196/10.
d^2= 28/22*196/10.
d= √25.

K.vignesh. said:   5 years ago
Good explanation, Thanks @Jack.

Monika said:   5 years ago
Thanks for the explanation.

Seenu said:   6 years ago
2*PI*R = 2*π*d/2*d/2.

Tirusew S. said:   6 years ago
Thank you all for the given explanation.

Harsha said:   7 years ago
Stress = force/area.
Area = force/stress,
Area = 1960/100=19.6.
πdd/4=19.6,
dd/4=19.6/3.14,
dd=6.24*4,
d= √24.96,
d=5mm.
(1)

Maitri said:   7 years ago
Thanks @Jack.

KRISHNA said:   7 years ago
Nice explanation. Thanks.

Vikram singh said:   8 years ago
Very good explanation @Jack.