Civil Engineering - Surveying - Discussion


The probable error of the adjusted bearing at the middle is

[A]. rn
[B]. rn
[C]. rn
[D]. rn.

Answer: Option A


No answer description available for this question.

Pankaj Yadav said: (May 3, 2017)  
Give the description of the answer.

Tapu said: (Aug 19, 2018)  
Anyone give the description of the answer.

Sorbottam Ghosh said: (Oct 27, 2018)  
Please explain the answer.

Prabhat said: (Nov 6, 2018)  
Its just like error at nth station =n*e/N in link traverse.

Here, a probable error at initial=0, similarly at the end is r√(n).

At middle would be averagei .e=r* √(n)/2.

Shally said: (Jun 12, 2020)  

What "r" denotes?

Peter said: (Aug 18, 2020)  
I think;

r = error in one link.
n = total no of links.
Initial error = 0.
Error at end = r√n,
Error at middle = avg.
= (0 + r√n) 2
= r√n.

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