Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 39)
39.
The probable error of the adjusted bearing at the middle is
rn
rn
rn
rn.Discussion:
6 comments Page 1 of 1.
Peter said:
5 years ago
I think;
r = error in one link.
n = total no of links.
Initial error = 0.
Error at end = r√n,
Error at middle = avg.
= (0 + r√n) 2
= r√n.
r = error in one link.
n = total no of links.
Initial error = 0.
Error at end = r√n,
Error at middle = avg.
= (0 + r√n) 2
= r√n.
(2)
Shally said:
5 years ago
@Prabhat
What "r" denotes?
What "r" denotes?
Prabhat said:
7 years ago
Its just like error at nth station =n*e/N in link traverse.
Here, a probable error at initial=0, similarly at the end is r√(n).
At middle would be averagei .e=r* √(n)/2.
Here, a probable error at initial=0, similarly at the end is r√(n).
At middle would be averagei .e=r* √(n)/2.
(3)
Sorbottam ghosh said:
7 years ago
Please explain the answer.
Tapu said:
7 years ago
Anyone give the description of the answer.
Pankaj yadav said:
8 years ago
Give the description of the answer.
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