Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 2)
2.
If h is the difference in level between end points separated by l, then the slope correction is 
. The second term may be neglected if the value of h in a 20 m distance is less than
. The second term may be neglected if the value of h in a 20 m distance is less than
m1 m
2 m
3 m
Discussion:
67 comments Page 5 of 7.
Rajesh said:
1 decade ago
How it comes 3.3?
Rajesh said:
1 decade ago
How it comes 3.3?
AKSHAY VASHISHT said:
1 decade ago
Second term is neglected for slope less than 10%.
Slope for given problem for:
C) (2/20)*100 = 10%.
D) (3/20)*100 = 15%.
So for h = 2 m or less it is neglected.
And for h = 3 m it will be taken into account.
Slope for given problem for:
C) (2/20)*100 = 10%.
D) (3/20)*100 = 15%.
So for h = 2 m or less it is neglected.
And for h = 3 m it will be taken into account.
Deepesh said:
9 years ago
Two things I found in this discussion,
1) For a slope smaller than 10%, Slope correction = h^2/2l, and,
2) For a slope greater than 10%, Slope correction = h^2/2l + h^4/8l^3 should use.
But finally, I did not get the answer 3 or 3.333.
Please anybody explains this answer in detail.
Thanks in advance;).
1) For a slope smaller than 10%, Slope correction = h^2/2l, and,
2) For a slope greater than 10%, Slope correction = h^2/2l + h^4/8l^3 should use.
But finally, I did not get the answer 3 or 3.333.
Please anybody explains this answer in detail.
Thanks in advance;).
Siva said:
1 decade ago
h2 = 40 root 40 = 6.32.
How can you get 3.3?
How can you get 3.3?
Ramu said:
1 decade ago
Answer is 1
From answer verification, If we substitute 1/2 in second term then it will negligible compared to other.
From answer verification, If we substitute 1/2 in second term then it will negligible compared to other.
Rashmi said:
1 decade ago
How 3.30?
Nanda said:
1 decade ago
@Vijay patel.
h2 = 2*20
h square = 40.
How come h = 3.3?
h2 = 2*20
h square = 40.
How come h = 3.3?
VIVEK CHANDEL said:
1 decade ago
For slopes of 10 percent or less, the correction to be applied to L for a difference d in elevation between tape ends, or for a horizontal offset d between tape ends, may be computed from,
Cs=(h^2)/(2L).
For a slope greater than 10 percent, Cs may be determined from,
Cs={(h^2)/(2L)}+{(h^4)/8(L^3)}.
Cs=(h^2)/(2L).
For a slope greater than 10 percent, Cs may be determined from,
Cs={(h^2)/(2L)}+{(h^4)/8(L^3)}.
Aman said:
1 decade ago
If we use any value lesser than 3 and not greater than 3, then answer for slope correction either using the complete formula given above or by eliminating the second term, we will get the same answer. Thus it means that the second term can be eliminated the right answer is 3 and distance kept as 20m.
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