Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 2)
2.
If h is the difference in level between end points separated by l, then the slope correction is 
. The second term may be neglected if the value of h in a 20 m distance is less than
. The second term may be neglected if the value of h in a 20 m distance is less than
m1 m
2 m
3 m
Discussion:
68 comments Page 1 of 7.
Khagendra said:
5 years ago
For slope (M) up to 20%.
Slope correction(Sc) = h^2/(2l).
Here d = 20m,
M = h/d,
0.2 = h/20.
H = 0.2 * 20 = 4m.
Here the nearest one is 3m.
So 3m is the appropriate answer.
Slope correction(Sc) = h^2/(2l).
Here d = 20m,
M = h/d,
0.2 = h/20.
H = 0.2 * 20 = 4m.
Here the nearest one is 3m.
So 3m is the appropriate answer.
(17)
NARDOS TEFERI said:
2 years ago
For slope (M) up to 20%.
According to me, the solution is;
Slope correction(Sc) = h^2/(2l).
Here d = 20m,
M = h/d,
0.2 = h/20.
H = 0.2 * 20 = 4m.
According to me, the solution is;
Slope correction(Sc) = h^2/(2l).
Here d = 20m,
M = h/d,
0.2 = h/20.
H = 0.2 * 20 = 4m.
(14)
Chaan A said:
3 years ago
Explain it clearly.
(7)
Dev Narayan Yadav said:
4 years ago
l = 20 m.
H2 = 2l,
H2 = 2*20,
H2 = 40.
And;
H = 6.32 or 6.33,
√40 = 6.32.
H2 = 2l,
H2 = 2*20,
H2 = 40.
And;
H = 6.32 or 6.33,
√40 = 6.32.
(7)
Mukesh das said:
4 years ago
How it will be 3m?
Please explain clearly with the completed formula.
Please explain clearly with the completed formula.
(5)
Aazad said:
4 years ago
Second term will be neglected when h=3cm not 3meter for length 20 meter.
(4)
Mukesh das said:
4 years ago
How it will be 3m?
Please explain clearly with the completed formula.
Please explain clearly with the completed formula.
(4)
Nandhu said:
5 years ago
The second term can be negleted only if the slopes flatter than 1 in 25..
That means 4%.
i.e, 4% of 20m = 0.8(4/5) ie, H shouldn't higher than 0.8m.
So option A is right.
That means 4%.
i.e, 4% of 20m = 0.8(4/5) ie, H shouldn't higher than 0.8m.
So option A is right.
(4)
LATHA said:
7 years ago
H^2=2*20.
=6.32.
SUBSTITUTE THE VALUE IN THE FORMULA.
6.32^2/2*20+6.32^4/8*(20^3).
0.998+2.492=3.4 (approx).
=6.32.
SUBSTITUTE THE VALUE IN THE FORMULA.
6.32^2/2*20+6.32^4/8*(20^3).
0.998+2.492=3.4 (approx).
(2)
Logeshkanna said:
6 years ago
The answer should be A. 1/2m.
With ref of Punmia : the second term in slope correction shall be neglected for slopes flatter than about 1 in 25 (i.e slope should be lesser than 0.04).
The slope is Vertical distance/Horizontal distance.
.
Here Vertical distance is h and the horizondal distance is √((L)^2 - (h)^2).
L = 20 given in the problem. We need to find, for which value of h the slope will be less than 0.04.
Sub h = 0.5, we get slope = 0.025;
Sub h = 1, we get slope = 0.050;
Sub h = 2, we get slope = 0.100;
Sub h = 3, we get slope = 0.150;
Therefore Option A (h=0.5m) is the correct answer.
With ref of Punmia : the second term in slope correction shall be neglected for slopes flatter than about 1 in 25 (i.e slope should be lesser than 0.04).
The slope is Vertical distance/Horizontal distance.
.
Here Vertical distance is h and the horizondal distance is √((L)^2 - (h)^2).
L = 20 given in the problem. We need to find, for which value of h the slope will be less than 0.04.
Sub h = 0.5, we get slope = 0.025;
Sub h = 1, we get slope = 0.050;
Sub h = 2, we get slope = 0.100;
Sub h = 3, we get slope = 0.150;
Therefore Option A (h=0.5m) is the correct answer.
(1)
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