Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 2)
2.
If h is the difference in level between end points separated by l, then the slope correction is 
. The second term may be neglected if the value of h in a 20 m distance is less than
. The second term may be neglected if the value of h in a 20 m distance is less than
m1 m
2 m
3 m
Discussion:
67 comments Page 5 of 7.
Naga Raju CH said:
9 years ago
h^2/2l = 1.
h^2/2 * 20 = 1,
h^2/40 = 1.
h^2 = 40.
Therefore(h) =6.32 (how will come 3 answer plz explain briefly).
h^2/2 * 20 = 1,
h^2/40 = 1.
h^2 = 40.
Therefore(h) =6.32 (how will come 3 answer plz explain briefly).
Simha said:
9 years ago
Not getting this. Please explain briefly.
Irfan said:
9 years ago
How 3.3? Explain in detail.
Pravin Pawar said:
9 years ago
For slope greater than 5% closer a closer approximation of corrected slope can be determined by h2/2l + h4/8l3.
Otherwise taken as h2/2l.
In the above example slope taken as 5% of length.
Length = 20 m therefore slope is 1.
Slope = height/length.
We have slope value equal to 1.
Then h2/2l = 1.
Answer is 6.32 m which is more than 3.
Otherwise taken as h2/2l.
In the above example slope taken as 5% of length.
Length = 20 m therefore slope is 1.
Slope = height/length.
We have slope value equal to 1.
Then h2/2l = 1.
Answer is 6.32 m which is more than 3.
Imran Hossain said:
9 years ago
** If h is the difference in level between endpoints separated by l, then the slope correction is c=(h^2/2l)+{h^4/8(l^3)}.
** If h is less than 3m in a length often the 20 m, then the quantity h^4/8(l^3) can be neglected. Hence c = h^2/2l.
Source. Dr. B.C. Punmia.
** If h is less than 3m in a length often the 20 m, then the quantity h^4/8(l^3) can be neglected. Hence c = h^2/2l.
Source. Dr. B.C. Punmia.
Mahavicky said:
9 years ago
How h come in the answer?
Yps said:
9 years ago
The answer is 3 cm, not 3 m.
Vinay said:
9 years ago
How come h = 3.3?
Rihaan said:
9 years ago
@Vijay.
How, 3.3?
How, 3.3?
Deepesh said:
9 years ago
Two things I found in this discussion,
1) For a slope smaller than 10%, Slope correction = h^2/2l, and,
2) For a slope greater than 10%, Slope correction = h^2/2l + h^4/8l^3 should use.
But finally, I did not get the answer 3 or 3.333.
Please anybody explains this answer in detail.
Thanks in advance;).
1) For a slope smaller than 10%, Slope correction = h^2/2l, and,
2) For a slope greater than 10%, Slope correction = h^2/2l + h^4/8l^3 should use.
But finally, I did not get the answer 3 or 3.333.
Please anybody explains this answer in detail.
Thanks in advance;).
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