Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 2)
2.
If h is the difference in level between end points separated by l, then the slope correction is 
. The second term may be neglected if the value of h in a 20 m distance is less than
. The second term may be neglected if the value of h in a 20 m distance is less than
m1 m
2 m
3 m
Discussion:
68 comments Page 3 of 7.
NARDOS TEFERI said:
2 years ago
For slope (M) up to 20%.
According to me, the solution is;
Slope correction(Sc) = h^2/(2l).
Here d = 20m,
M = h/d,
0.2 = h/20.
H = 0.2 * 20 = 4m.
According to me, the solution is;
Slope correction(Sc) = h^2/(2l).
Here d = 20m,
M = h/d,
0.2 = h/20.
H = 0.2 * 20 = 4m.
(14)
Aadil said:
8 years ago
The second term may safely be neglected for slopes flatter than about 1 in 25. Therefore,
h^2/2l=25%.
H^2/2*20=0.25,
H^2=10,
H=3.16.=3 (approx).
h^2/2l=25%.
H^2/2*20=0.25,
H^2=10,
H=3.16.=3 (approx).
Aniket said:
8 years ago
In (h^4) / (8l^3), The Value comes out 0.008 (Almost 0%) up to filling of h=2.9. At h=3m the value comes out 0.01.
so, h=3 is the right answer.
so, h=3 is the right answer.
Ajaypal singh nirala said:
6 years ago
If the value of h is maximum then h^4 value is greater than the other value. So how is possible to this? Value goes nearest to zero right?
BALA said:
8 years ago
In this case, if we neglected 2nd term the correction should be less 20%. So,(h^2/2x20)<20% or 0.2. results h<2.828 m.
Shiv said:
6 years ago
Correct @Imran.
As we decrease the value of h less than 3, the second term impact becomes negligence so 3 is the answer.
As we decrease the value of h less than 3, the second term impact becomes negligence so 3 is the answer.
Ramu said:
1 decade ago
Answer is 1
From answer verification, If we substitute 1/2 in second term then it will negligible compared to other.
From answer verification, If we substitute 1/2 in second term then it will negligible compared to other.
LATHA said:
7 years ago
H^2=2*20.
=6.32.
SUBSTITUTE THE VALUE IN THE FORMULA.
6.32^2/2*20+6.32^4/8*(20^3).
0.998+2.492=3.4 (approx).
=6.32.
SUBSTITUTE THE VALUE IN THE FORMULA.
6.32^2/2*20+6.32^4/8*(20^3).
0.998+2.492=3.4 (approx).
(2)
Naga Raju CH said:
9 years ago
h^2/2l = 1.
h^2/2 * 20 = 1,
h^2/40 = 1.
h^2 = 40.
Therefore(h) =6.32 (how will come 3 answer plz explain briefly).
h^2/2 * 20 = 1,
h^2/40 = 1.
h^2 = 40.
Therefore(h) =6.32 (how will come 3 answer plz explain briefly).
Ghalib said:
8 years ago
For slope less than 1 in 25 so h/l is less than or eqal to1 in 25 so h is q.
Equal to or less than (.8).
Equal to or less than (.8).
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