Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 1 (Q.No. 22)
22.
Two concave lenses of 60 cm focal length are cemented on either side of a convex lens of 15 cm focal length. The focal length of the combination is
10 cm
20 cm
30 cm
40 cm
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
38 comments Page 1 of 4.

Neeraj Kumar singh said:   4 years ago
1/f = 1/15 - 1/60 - 1/60.
1/f = 1/30,
F = 30.
(5)

Poj said:   4 years ago
Concave (-) and convex (+).

Given:
Two concave i.e F1 = -1/60.
F2 = -1/60.

One convex lens i.e F3 = 1/15.
combined focal length = (F1 + F2) + F3.
= { ( -1/60) + ( -1/60) } + 1/15,
= (-2/60) + 1/15,
= -1/30 + 1/15,
= -1+2/30,
= 1/30 = 30.
(27)

NAVEEN said:   5 years ago
1/f = 1/F1+1/F2.
1/60 = 1/15+1/F2.
F = 30.
(7)

Dev Kumavat said:   6 years ago
Thank you @Sameer Kashmiri.

TSKD said:   7 years ago
Since two cancave is sandwitched with one convex ie.,
1/f = 1/60 + 1/60 - 1/15,
1/f = 1/30.
(6)

Rashmi said:   7 years ago
Please explain me the answer.
(1)

Sammy said:   7 years ago
Simple.

1/f = -1/f -1/f + 1/f.
1/ f= -1/60 -1/60 + 1/15.
1/f= -1/30 + 1/15.
1/f= 1/30.
F=30.

Hariom said:   7 years ago
Yes. It is 30.

Julia roberts said:   8 years ago
1/f=1/f1+1/f2.
concave=-ve.
convex=+ve.
1/f=1/15-(1/60+1/60).
.: f=30.
(1)

AKSHAY GUPTA said:   8 years ago
Formula: 1/f = 1/f1 + 1/f2.

According to the problem 60 cm on the either side i.e. f1 = f2 = 60 & focal length combination f = ?
Now, 1/f = 1/f1 + 1/f2.
1/f = 1/60 + 1/60.
= 1/30. So combination is 30.


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