Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 43)
43.
If the long chord and tangent length of a circular curve of radius R are equal the angle of deflection, is
Discussion:
9 comments Page 1 of 1.
John said:
4 years ago
Thanks @Abdul Aziz.
Waqas said:
5 years ago
Thanks @Abdul Aziz.
ABDUL AZIZ said:
5 years ago
Long chord = 2R*sinθ/2, and,
For Tangent length= R* tanθ/2.
A/c to question,
Long chord = tangent length.
2R * sinθ/2 = R * tanθ/2.
=> 2 sinθ/2 = (sinθ/2 ÷cosθ/2)
=> 2 = 1÷ cosθ/2.
=> cosθ/2 = 1/2 = cos60°
=> θ/2 = 60.
=> θ =120.
For Tangent length= R* tanθ/2.
A/c to question,
Long chord = tangent length.
2R * sinθ/2 = R * tanθ/2.
=> 2 sinθ/2 = (sinθ/2 ÷cosθ/2)
=> 2 = 1÷ cosθ/2.
=> cosθ/2 = 1/2 = cos60°
=> θ/2 = 60.
=> θ =120.
(2)
Masood said:
5 years ago
Thanks @Jeet Beniwal.
Josh said:
7 years ago
If LC = T, then you have an equilateral triangle: 60-60-60.
The deflection angle at the PI is simply 180 - interior angle 60 = 120.
The deflection angle at the PI is simply 180 - interior angle 60 = 120.
(2)
Ngm said:
8 years ago
How to get 60?
Ngm said:
8 years ago
How to comes (θ/2)?
Jeet beniwal said:
8 years ago
Long chord = 2*Rsinθ/2,
Tangent = Rtanθ/2.
Equating both, we get,
θ/2 = 60.
θ =120.
Tangent = Rtanθ/2.
Equating both, we get,
θ/2 = 60.
θ =120.
(1)
Shahid Malik said:
8 years ago
Anyone explain this question clearly.
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