Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 5 (Q.No. 49)
49.
A sewer is laid from a manhole A to a manhole B, 250 m away along a gradient of 1 in 125. If the reduced level of the invert at A is 205.75 m and the height of the boning rod is 3 m, the reduced level of the sight rail at B, is
Discussion:
16 comments Page 2 of 2.
Piku said:
8 years ago
205.75-(1 * 250/150)+3 = 206.75.
Gaurav said:
8 years ago
Gradient is downward.
Chadha said:
8 years ago
205.75 - (250*1/125-3)= 206.75.
Rajib kumar said:
7 years ago
Please explain the solution.
Mahesh said:
6 years ago
RL of invert at B.
= 205.75 - (250 ÷ 125) = 203.75.
RL of sight at B = 203.75+3 = 206.75.
= 205.75 - (250 ÷ 125) = 203.75.
RL of sight at B = 203.75+3 = 206.75.
Dawood khan said:
5 years ago
Thankyou for the explanation @Xavi.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers