Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 7 (Q.No. 41)
41.
The staff reading at a distance of 80 m from a level with the bubble at its centre is 1.31 m. When the bubble is moved by 5 divisions out of the centre, the reading is 1.39 m. The angular value of the one division of the bubble, is
Discussion:
10 comments Page 1 of 1.
Shubham P said:
5 years ago
We know angular value, α =( S/nD) * 206265.
Here.
S = Staff intercept = 1.39 - 1.31 = 0.08 meter.
n = number of division given for change in reading = 5 divisions.
D = linear distance between instrument and Staff = 80 meter.
& multiplied by 206265 to convert an angular value from radian to seconds.
Put the values and answer will be 41.253 seconds per division.
Here.
S = Staff intercept = 1.39 - 1.31 = 0.08 meter.
n = number of division given for change in reading = 5 divisions.
D = linear distance between instrument and Staff = 80 meter.
& multiplied by 206265 to convert an angular value from radian to seconds.
Put the values and answer will be 41.253 seconds per division.
(5)
Jay Ghosh said:
10 years ago
206265 = s/d.
s = 1.39-1.31 = 0.08 m/5 div.
= (206265*0.08)/80.
= 206.265 sec/5 div.
= (206.265*1)/5.
= 41.253 sec/1 div.
Answer B.
s = 1.39-1.31 = 0.08 m/5 div.
= (206265*0.08)/80.
= 206.265 sec/5 div.
= (206.265*1)/5.
= 41.253 sec/1 div.
Answer B.
(1)
Shubham said:
8 years ago
How 206.265? @Jay Ghosh.
Garry said:
8 years ago
It is total angular division not of 1 div value.
Nayan said:
8 years ago
1 degree = 3600 sec.
1 radian =180 degree =57.2958°.
1 radian = 206265" second.
1 radian =180 degree =57.2958°.
1 radian = 206265" second.
Gaurav said:
8 years ago
α =( s/nD)*206265.
Amy said:
6 years ago
Thanks @Gaurav.
Gurdarshan Singh said:
5 years ago
Please answer with full explanation.
Himansh said:
5 years ago
Nice @Shubham.
Indar said:
5 years ago
Thanks for the explanation @Shubham P.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers