Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 40)
40.
The bearings of the lines AB and BC are 146° 30' and 68° 30'. The included angle ABC is
Discussion:
40 comments Page 2 of 4.
PRAVESH VERMA said:
10 years ago
Both f.b.
So BC of B.B =68°30'+180° = 248°30'.
AB of f.b. = 146°30'.
/ABC = 248°30' - 146°30' = 102° answer.
So BC of B.B =68°30'+180° = 248°30'.
AB of f.b. = 146°30'.
/ABC = 248°30' - 146°30' = 102° answer.
Leo said:
8 years ago
Option d is right.
Becuase when bearing of two line measured not from their point of intersection. The rule of finding angle as different.
Becuase when bearing of two line measured not from their point of intersection. The rule of finding angle as different.
Shramik shanti said:
7 years ago
Applying formula..Included angle = f.b of next line - b.b of previous line.
= f.b of BC - b.b of AB.
= 68.30 - 146.30.
= 78.
+180 = 102.
= f.b of BC - b.b of AB.
= 68.30 - 146.30.
= 78.
+180 = 102.
(2)
Mohmmed said:
6 years ago
The Azimuth of a line AB is 114 and the angle ABC 126°30'20". Calculate the Bearing of BC?
Please answer this.
Please answer this.
Aadarsh Devkate said:
7 years ago
180°-146°30°= 33°30°00°.
So,
<ABC = 68°30°+ 33°30°00° = 102°.
So,
<ABC = 68°30°+ 33°30°00° = 102°.
Indrajit Maiti said:
8 years ago
The bb of AB - fb of BC = {(180°+146°30')- 68°30'}= 258°,
Angle = (360°-258°) =102°.
Angle = (360°-258°) =102°.
Sumit said:
5 years ago
In finding true angle (satellite station) reduction to center, then which formula is used? Please tell me.
Saurabh kumar said:
8 years ago
As per my knowledge, Interior angle = BB of AB - FB of BC.
Are interior angle and included angle same.
Are interior angle and included angle same.
KAN said:
7 years ago
BB of AB + FB of BC.
BB of AB is 180-146.30 = 33.30,
FB of BC is 68.30.
So, 33.30 + 68.30 = 102.
BB of AB is 180-146.30 = 33.30,
FB of BC is 68.30.
So, 33.30 + 68.30 = 102.
Rakesh Kumar Baral said:
7 years ago
AB = 107*15'.
BC= 22*00'.
AB-BC= 107*15-22*00= 85*15'.
Included angle ABC= 180*-85*15'= 94*45'.
BC= 22*00'.
AB-BC= 107*15-22*00= 85*15'.
Included angle ABC= 180*-85*15'= 94*45'.
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