Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 2 (Q.No. 14)
14.
The desired sensitivity of a bubble tube with 2 mm divisions is 30". The radius of the bubble tube should be
Discussion:
18 comments Page 1 of 2.
SHRUTI said:
3 years ago
The right answer is A.
Chad Quincy Cablitas said:
3 years ago
Formulas:
alpha(") = s/nDsin1"
R = nLD/s.
Manipulating the formulas, we know that:
R = (1/alpha(")*sin(1"))*L,
R= 13.75.
alpha(") = s/nDsin1"
R = nLD/s.
Manipulating the formulas, we know that:
R = (1/alpha(")*sin(1"))*L,
R= 13.75.
Philven said:
3 years ago
The formula is radius equals to the [sensitiveness] divided by [division (in seconds) multiplied by sine 1 second].
Radius= 2mm/30"
= 13750.987 mm (convert to meters)
= 13.75.
Radius= 2mm/30"
= 13750.987 mm (convert to meters)
= 13.75.
(3)
Colis said:
4 years ago
How can the radius of the bubble tube = 13.75 m? Explain, please.
(3)
Moin said:
5 years ago
For 2 mm divisions,
sensitivity = 412.43/R.
This is a simple way to remember it. In general, sensitivity = 206265 * d/R.
sensitivity = 412.43/R.
This is a simple way to remember it. In general, sensitivity = 206265 * d/R.
(1)
Roohullah jan said:
5 years ago
It's quite simple guys.
As we know S=R* π --->1)
Where R is radius and π is Central angle in radian.
So S= 2mm.
π= 30" remember 1"= 0.00000484814 so 30" becomes 30* 0.00000484814= 0.0001454441 rad.
Equation (1)=> 2=R*0.0001454441.
R= 13750.98mm => 13.75 m.
As we know S=R* π --->1)
Where R is radius and π is Central angle in radian.
So S= 2mm.
π= 30" remember 1"= 0.00000484814 so 30" becomes 30* 0.00000484814= 0.0001454441 rad.
Equation (1)=> 2=R*0.0001454441.
R= 13750.98mm => 13.75 m.
(3)
Anjali said:
6 years ago
How the radius is inverse to sensitiveness?
(1)
Kesavan said:
7 years ago
Sensitivity = (D/R)*205265.
so, we need R=(D/sensitivity)*206265.
R = (0.002/30)*206265.
R = 13.75 m.
so, we need R=(D/sensitivity)*206265.
R = (0.002/30)*206265.
R = 13.75 m.
(9)
Tanmoy karmakar said:
7 years ago
30'' = 2mm,
1' = 4mm,
1° = 240mm,
360° = 240*360 = 86400mm,
2*π*r = 86400,
So, r = 13757.9mm = 13.75 m.
1' = 4mm,
1° = 240mm,
360° = 240*360 = 86400mm,
2*π*r = 86400,
So, r = 13757.9mm = 13.75 m.
(8)
MD FAISAL said:
8 years ago
In 30'----2mm.
So 360°=?
(360*60*60)'*2mm/30'=length of circumference.
So Lc=2*3.14*R.
(360*60*60)'*2/30'=2*3.14*R.
R=13.75m.
So 360°=?
(360*60*60)'*2mm/30'=length of circumference.
So Lc=2*3.14*R.
(360*60*60)'*2/30'=2*3.14*R.
R=13.75m.
(2)
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