Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 4 (Q.No. 46)
46.
A standard steel tape of length 30 m and cross-section 15 x 1.0 mm was standardised at 25°C and at 30 kg pull. While measuring a base line at the same temperature, the pull applied was 40 kg. If the modulus of elasticity of steel tape is 2.2 x 106 kg/cm2, the correction to be applied is
Discussion:
27 comments Page 1 of 3.
Rana said:
2 years ago
I think option C will be the correct answer.
(2)
Avik said:
5 years ago
The right Answer is +0.00909m.
(2)
Ajmal Khan said:
9 years ago
No, @Satish the answer A is correct because the standard pull is 30 Kg and applied pull is 40 Kg, so the tape will measure long distance than actual, so the final result must be subtracted from measured distance. That's why it is negative one.
(1)
Deeksha said:
4 years ago
30 m steel tape was standardized under 60 N pull at 65° F.
It was suspended in 5 equal span during measurement. The mean temperature during measurement was 90° F and the pull exerted was 100 N. The area of the cross-section of the tape was 8 mm2. Find the true length of the tape, if, α = 6.3 * 10^6/F, E = 2 *105 N/mm2 and unit weight of steel = 78.6 kN/m3.
It was suspended in 5 equal span during measurement. The mean temperature during measurement was 90° F and the pull exerted was 100 N. The area of the cross-section of the tape was 8 mm2. Find the true length of the tape, if, α = 6.3 * 10^6/F, E = 2 *105 N/mm2 and unit weight of steel = 78.6 kN/m3.
(1)
Ankit Gautam said:
6 years ago
Yes, it should be option C.
(1)
Abhilash said:
7 years ago
@All.
The correction is opposite of error so it should be negative.
The correction is opposite of error so it should be negative.
(1)
Debabrata said:
7 years ago
I think C is the right answer.
Shahab Mehsud said:
4 years ago
I think option C is correct; as the tape elongated due to extra pull applied, hence the measured length will be less than the actual.
Jinx said:
4 years ago
The error is +ive but at the end of the question, "correction to be applied" has been asked. Which makes option A correct. The value of error is positive so we will deduct it from the final value, so the applied correction will be -0. 000909m.
Vishal Vishwakarma said:
5 years ago
Correction should be positive since we measured longer than actual it was, mean that suppose we have seen on tape length is 150m while measurement but actual it was more than that of 150m, let say 151 m actual therefore to obtain this from 150 to 151m.
We need correction positive.
So, the right option will be C.
We need correction positive.
So, the right option will be C.
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