Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 48)
48.
ABCD is a regular parallelogram plot of land whose angle BAD is 60°. If the bearing of the line AB is 30°, the bearing of CD, is
Discussion:
16 comments Page 2 of 2.
Sandip mondal said:
9 years ago
<ABC=180°-60°=120°.
FB of AB=30°
BB of AB=30°+180°=210°
FB of BC=210°+<ABC=210°+120°=330°
BB of BC=330-180=150
FB of CD=150+<BAD=150+60=210°.
FB of AB=30°
BB of AB=30°+180°=210°
FB of BC=210°+<ABC=210°+120°=330°
BB of BC=330-180=150
FB of CD=150+<BAD=150+60=210°.
(1)
HITESH KUMAR said:
1 decade ago
Bearing of CD = 180+30 = 210.
Debashis Mahato said:
1 decade ago
How its possible?
Raj said:
1 decade ago
Back Bearing-Fore Bearing = 180.
So BB-30 = 180,
Now, BB = 180+30 = 210.
So BB-30 = 180,
Now, BB = 180+30 = 210.
Nikhil said:
10 years ago
Thanks for the brief description @Darshan H A.
Shree g said:
10 years ago
Thanks for the brief description.
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