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Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 1 (Q.No. 48)
Surveying
48.
ABCD is a regular parallelogram plot of land whose angle BAD is 60°. If the bearing of the line AB is 30°, the bearing of CD, is
90°
120°
210°
270°
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.
Tushar Methiya said:   6 years ago
Bearing of AB is 30 & BAD is 60 then for CD angle is 180+30 = 210.
(10)
Prepared said:   7 years ago
210°-180°=30°+30°=60°.

So 210° is the right answer.
(4)
Bhawna said:   7 years ago
Can anyone explain this with the help of pictorial representation?
(4)
Kuldeep nautiyal said:   8 years ago
Bearing of BC = bearing of BA + angle B.
B of BC = 30+180+120.

Bearing of CD = bearing of CB + angle C.
Bearing of CD = (330 - 180) + 60.

Angle B + angle A = 180 (sum of consecutive angle of a parallelogram are 180).
(7)
CHANDAN KUMAR SINGH said:   8 years ago
ANSWER-- C
Bearing of AB =Bearing of DC BECAUSE regular parallelogram.
Bearing of DC = 30 DEGREE.
NOW bearing of CD = BB of DC =180+30=210 DEGREE.
(11)
Sandip mondal said:   8 years ago
<ABC=180°-60°=120°.
FB of AB=30°
BB of AB=30°+180°=210°
FB of BC=210°+<ABC=210°+120°=330°
BB of BC=330-180=150
FB of CD=150+<BAD=150+60=210°.
(1)
Hitesh Singh said:   8 years ago
Here, 180 + 30 = 210.
(1)
Shree g said:   9 years ago
Thanks for the brief description.
Nikhil said:   9 years ago
Thanks for the brief description @Darshan H A.
Manatosh said:   10 years ago
FB of line CD = BB of line AB.
= FB of AB + 180°.
= 30°+180° = 210°.
(2)
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