Civil Engineering - Surveying - Discussion

48. 

ABCD is a regular parallelogram plot of land whose angle BAD is 60°. If the bearing of the line AB is 30°, the bearing of CD, is

[A]. 90°
[B]. 120°
[C]. 210°
[D]. 270°

Answer: Option C

Explanation:

No answer description available for this question.

Hitesh Kumar said: (Jan 17, 2014)  
Bearing of CD = 180+30 = 210.

Debashis Mahato said: (Nov 28, 2014)  
How its possible?

Mohammed Libinshad. K said: (Apr 5, 2015)  
Since it is a regular pentagon.

i.e. Bearing of AB = Bearing of DC.

=> Bearing of CD = Back bearing of DC.

= Back bearing of AB = 180+30 = 210.

Raj said: (Jun 27, 2015)  
Back Bearing-Fore Bearing = 180.

So BB-30 = 180,

Now, BB = 180+30 = 210.

Mohan Cenation said: (Sep 19, 2015)  
The bearing of AB is 30*.

Since, it is less than 90*. So, we have to add 180* for it.

Then it is (30*+180*=210*).

Darshan H A said: (Dec 29, 2015)  
Total interior angle = (2n-4)*90 where n=4, no of sides.

There fore total interior angle = ((2*4)-4)*90 = 360. Each included angle = total interior angle/n = 360/4 =90.

The defection angle = 180-each included angle = 180-90 = 90.

Then fore bearing of any line = Deflection angle + Fore bearing of previous line.

Fore bearing of AB = 30, fore bearing of BC = 90+30 = 120, fore bearing of CD = 90+120 = 210, fore bearing of DA = 90+210 = 300.

Manatosh said: (Mar 15, 2016)  
FB of line CD = BB of line AB.
= FB of AB + 180°.
= 30°+180° = 210°.

Nikhil said: (Jan 11, 2017)  
Thanks for the brief description @Darshan H A.

Shree G said: (Feb 13, 2017)  
Thanks for the brief description.

Hitesh Singh said: (Jun 13, 2017)  
Here, 180 + 30 = 210.

Sandip Mondal said: (Aug 1, 2017)  
<ABC=180°-60°=120°.
FB of AB=30°
BB of AB=30°+180°=210°
FB of BC=210°+<ABC=210°+120°=330°
BB of BC=330-180=150
FB of CD=150+<BAD=150+60=210°.

Chandan Kumar Singh said: (Sep 14, 2017)  
ANSWER-- C
Bearing of AB =Bearing of DC BECAUSE regular parallelogram.
Bearing of DC = 30 DEGREE.
NOW bearing of CD = BB of DC =180+30=210 DEGREE.

Kuldeep Nautiyal said: (Nov 11, 2017)  
Bearing of BC = bearing of BA + angle B.
B of BC = 30+180+120.

Bearing of CD = bearing of CB + angle C.
Bearing of CD = (330 - 180) + 60.

Angle B + angle A = 180 (sum of consecutive angle of a parallelogram are 180).

Bhawna said: (Dec 29, 2018)  
Can anyone explain this with the help of pictorial representation?

Prepared said: (Jan 6, 2019)  
210°-180°=30°+30°=60°.

So 210° is the right answer.

Tushar Methiya said: (Sep 8, 2019)  
Bearing of AB is 30 & BAD is 60 then for CD angle is 180+30 = 210.

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