Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 3 (Q.No. 50)
The whole circle bearing of a line is 290°. Its reduced bearing is
N 20° E
N 20° W
N 70° W
S 70° E
Answer: Option
No answer description is available. Let's discuss.
9 comments Page 1 of 1.

Jero Momin said:   1 year ago
It's S70W if we go anti-clockwise, and N70W in clockwise.

But since there is only N70W in the options, so the right answer here is N70W.

Tribal Chief said:   2 years ago
Yes, I am agree with you, Thanks @Sanjay.

Sanjay Kumar Diwaker said:   2 years ago
The right answer will be S70° W.

MUHAMMAD said:   4 years ago
A bearing that defines the direction of a survey line by its horizontal angle measured clockwise from true north.

So it we go clockwise, it will fall in 4th quadrant i.e NW.
Hence, the correct answer is N70W.

Bharat Chaudhary said:   5 years ago
290° is in fourth quadrant.
RB = N(360 - 290)W.
= N70W.

AKSHAR TALAJIYA said:   5 years ago
I think the right answer is S 20° W.

Abhishek said:   6 years ago
Draw 290 on co-ordinates. It will under NW. Therefore 360-290 = N70W.

Priya said:   7 years ago
How can we say it is north-west direction?

CHADNAN said:   9 years ago
Reduced bearing = 360 degree (*)-whole circle bearing line.

= 360*-290* = 70*.

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