Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 8 (Q.No. 14)
14.
The bearing of line AB is 152° 30' and angle ABC measured clockwise is 124° 28'. The bearing of BC is
Discussion:
22 comments Page 2 of 3.
Nada said:
5 years ago
The reduced bearing of the centerline of two roads AB and AC are N 30° W and N 30° E respectively. These two roads connected by a third road BC. The length and the bearing of BC is 200 m and N 75° E. Find the length of AB and AC. Can anyone answer this?
Prashanth said:
5 years ago
For anticlockwise how to measure it?
Kripa said:
6 years ago
Then for angle AC?
Karthikranga said:
1 decade ago
How you get this answer can you explain the procedure for this?
Kanchan thakur said:
6 years ago
Bearing of AB=152°30'
<ABC=124°28'
Bearing of BC=?
Back bearing of AB = BA = F.B + 180 = 152°30' + 180° = 332°30'
Bearing of bc = b.b of AB+<ABC = 332°30' + 124°28' = 456°58'
This is more than 360 so;
Bearing of BC = 456°58' - 360° = 96°58'.
<ABC=124°28'
Bearing of BC=?
Back bearing of AB = BA = F.B + 180 = 152°30' + 180° = 332°30'
Bearing of bc = b.b of AB+<ABC = 332°30' + 124°28' = 456°58'
This is more than 360 so;
Bearing of BC = 456°58' - 360° = 96°58'.
Burhan Ali said:
6 years ago
FB of AB=152°30'
BB of AB=152°30 ' +180° = 332°30'
FB of BC = BB of AB at B=332 °30' + 124°28' = 456°58'.
= 456°58' - 360° = 96°58'(remember if angle is more then 360° Subtract 360°).
BB of AB=152°30 ' +180° = 332°30'
FB of BC = BB of AB at B=332 °30' + 124°28' = 456°58'.
= 456°58' - 360° = 96°58'(remember if angle is more then 360° Subtract 360°).
Adeel Rehman said:
6 years ago
Best Explanation, Thanks @Julliet Osunde.
Vikas Dubey said:
6 years ago
Bearing of any line = BB.of line + angle.
If angle is more than 180' than, -360'.
You will find the answer.
If angle is more than 180' than, -360'.
You will find the answer.
Aswathy said:
6 years ago
Forward Bearing of AB =152°30'
Back Bearing of AB= 180°-152°30=27°30'
FB of BC= Included angle - BB of AB
=124°28'-27°30'
=96°58'.
Back Bearing of AB= 180°-152°30=27°30'
FB of BC= Included angle - BB of AB
=124°28'-27°30'
=96°58'.
Alok said:
7 years ago
I am not getting the solution. Please, anyone explain me.
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