Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 8 (Q.No. 14)
14.
The bearing of line AB is 152° 30' and angle ABC measured clockwise is 124° 28'. The bearing of BC is
Discussion:
21 comments Page 1 of 3.
Prakash Pandey said:
5 months ago
Sum = WCB of AB + ∠B.
If Sum < 180° → WCB of BC = Sum + 180°.
If Sum ≥ 180° → WCB of BC = Sum - 180°.
If Sum ≥ 540° → WCB of BC = Sum - 540°.
If Sum < 180° → WCB of BC = Sum + 180°.
If Sum ≥ 180° → WCB of BC = Sum - 180°.
If Sum ≥ 540° → WCB of BC = Sum - 540°.
(1)
Rajan said:
1 year ago
Bearing of AB =152°30'.
Angle ABC = 124°28'.
Bearing BC = ?
Bearing BA = AB + 180 = 152°30' + 180°= 332°30'.
Bearing BC = AB + angle ABC = 332°30' + 124°28' = 456°58'.
Then 456°58' - 360° = 96°58'.
Angle ABC = 124°28'.
Bearing BC = ?
Bearing BA = AB + 180 = 152°30' + 180°= 332°30'.
Bearing BC = AB + angle ABC = 332°30' + 124°28' = 456°58'.
Then 456°58' - 360° = 96°58'.
(2)
Niranjan said:
4 years ago
FB of BC = FB of AB+<ABC+-180.
= 152 * 30' + 124 * 28'-180° (first two values sum is more than 180 so use -ve sign).
= 276 * 58'-180° = 96° 58'.
= 152 * 30' + 124 * 28'-180° (first two values sum is more than 180 so use -ve sign).
= 276 * 58'-180° = 96° 58'.
(6)
Philologue said:
4 years ago
Bearing of AB=152°30'.
Angle ABC = 124°28'.
Bearing BC=?
Bearing BA = AB + 180 = 152°30'+180°= 332°30'.
Bearing BC= AB + angle ABC = 332°30' + 124°28' = 456°58'.
Then 456°58'-360°= 96°58'.
Angle ABC = 124°28'.
Bearing BC=?
Bearing BA = AB + 180 = 152°30'+180°= 332°30'.
Bearing BC= AB + angle ABC = 332°30' + 124°28' = 456°58'.
Then 456°58'-360°= 96°58'.
(10)
Prakash Singh Thakuri said:
4 years ago
Fore bearing BC = back bearing AB + clockwise Angle ±180° ±540°.
BC = 152°30'+124°28'±180°±540°.
BC = 276°58'-180°.
BC = 96°58'.
Fore bearing BC=96°58' answer.
BC = 152°30'+124°28'±180°±540°.
BC = 276°58'-180°.
BC = 96°58'.
Fore bearing BC=96°58' answer.
(3)
Senthilnathan said:
4 years ago
Length AB = 163.29m and AC = 223.06m.
Nada said:
4 years ago
The reduced bearing of the centerline of two roads AB and AC are N 30° W and N 30° E respectively. These two roads connected by a third road BC. The length and the bearing of BC is 200 m and N 75° E. Find the length of AB and AC. Can anyone answer this?
Prashanth said:
5 years ago
For anticlockwise how to measure it?
MANVI said:
5 years ago
Please explain, how to calculate the angle AC?
Kripa said:
5 years ago
Then for angle AC?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers