# Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 8 (Q.No. 14)

14.

The bearing of line

*AB*is 152° 30' and angle*ABC*measured clockwise is 124° 28'. The bearing of*BC*isDiscussion:

20 comments Page 1 of 2.
Rajan said:
2 days ago

Bearing of AB =152°30'.

Angle ABC = 124°28'.

Bearing BC = ?

Bearing BA = AB + 180 = 152°30' + 180°= 332°30'.

Bearing BC = AB + angle ABC = 332°30' + 124°28' = 456°58'.

Then 456°58' - 360° = 96°58'.

Angle ABC = 124°28'.

Bearing BC = ?

Bearing BA = AB + 180 = 152°30' + 180°= 332°30'.

Bearing BC = AB + angle ABC = 332°30' + 124°28' = 456°58'.

Then 456°58' - 360° = 96°58'.

Niranjan said:
2 years ago

FB of BC = FB of AB+<ABC+-180.

= 152 * 30' + 124 * 28'-180° (first two values sum is more than 180 so use -ve sign).

= 276 * 58'-180° = 96° 58'.

= 152 * 30' + 124 * 28'-180° (first two values sum is more than 180 so use -ve sign).

= 276 * 58'-180° = 96° 58'.

(4)

Philologue said:
3 years ago

Bearing of AB=152°30'.

Angle ABC = 124°28'.

Bearing BC=?

Bearing BA = AB + 180 = 152°30'+180°= 332°30'.

Bearing BC= AB + angle ABC = 332°30' + 124°28' = 456°58'.

Then 456°58'-360°= 96°58'.

Angle ABC = 124°28'.

Bearing BC=?

Bearing BA = AB + 180 = 152°30'+180°= 332°30'.

Bearing BC= AB + angle ABC = 332°30' + 124°28' = 456°58'.

Then 456°58'-360°= 96°58'.

(8)

Prakash Singh Thakuri said:
3 years ago

Fore bearing BC = back bearing AB + clockwise Angle ±180° ±540°.

BC = 152°30'+124°28'±180°±540°.

BC = 276°58'-180°.

BC = 96°58'.

Fore bearing BC=96°58' answer.

BC = 152°30'+124°28'±180°±540°.

BC = 276°58'-180°.

BC = 96°58'.

Fore bearing BC=96°58' answer.

(2)

Senthilnathan said:
3 years ago

Length AB = 163.29m and AC = 223.06m.

Nada said:
3 years ago

The reduced bearing of the centerline of two roads AB and AC are N 30° W and N 30° E respectively. These two roads connected by a third road BC. The length and the bearing of BC is 200 m and N 75° E. Find the length of AB and AC. Can anyone answer this?

Prashanth said:
3 years ago

For anticlockwise how to measure it?

MANVI said:
4 years ago

Please explain, how to calculate the angle AC?

Kripa said:
4 years ago

Then for angle AC?

Kanchan thakur said:
4 years ago

Bearing of AB=152°30'

<ABC=124°28'

Bearing of BC=?

Back bearing of AB = BA = F.B + 180 = 152°30' + 180° = 332°30'

Bearing of bc = b.b of AB+<ABC = 332°30' + 124°28' = 456°58'

This is more than 360 so;

Bearing of BC = 456°58' - 360° = 96°58'.

<ABC=124°28'

Bearing of BC=?

Back bearing of AB = BA = F.B + 180 = 152°30' + 180° = 332°30'

Bearing of bc = b.b of AB+<ABC = 332°30' + 124°28' = 456°58'

This is more than 360 so;

Bearing of BC = 456°58' - 360° = 96°58'.

Post your comments here:

Your comments will be displayed after verification.

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers

© IndiaBIX™ Technologies