# Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 8 (Q.No. 14)
14.
The bearing of line AB is 152° 30' and angle ABC measured clockwise is 124° 28'. The bearing of BC is
27° 52'
96° 58'
148° 08'
186° 58'
Explanation:
No answer description is available. Let's discuss.
Discussion:
20 comments Page 1 of 2.

Rajan said:   2 days ago
Bearing of AB =152°30'.
Angle ABC = 124°28'.
Bearing BC = ?
Bearing BA = AB + 180 = 152°30' + 180°= 332°30'.
Bearing BC = AB + angle ABC = 332°30' + 124°28' = 456°58'.

Then 456°58' - 360° = 96°58'.

Niranjan said:   2 years ago
FB of BC = FB of AB+<ABC+-180.
= 152 * 30' + 124 * 28'-180° (first two values sum is more than 180 so use -ve sign).
= 276 * 58'-180° = 96° 58'.
(4)

Philologue said:   3 years ago
Bearing of AB=152°30'.
Angle ABC = 124°28'.
Bearing BC=?
Bearing BA = AB + 180 = 152°30'+180°= 332°30'.
Bearing BC= AB + angle ABC = 332°30' + 124°28' = 456°58'.

Then 456°58'-360°= 96°58'.
(8)

Prakash Singh Thakuri said:   3 years ago
Fore bearing BC = back bearing AB + clockwise Angle ±180° ±540°.
BC = 152°30'+124°28'±180°±540°.
BC = 276°58'-180°.
BC = 96°58'.
(2)

Senthilnathan said:   3 years ago
Length AB = 163.29m and AC = 223.06m.

The reduced bearing of the centerline of two roads AB and AC are N 30° W and N 30° E respectively. These two roads connected by a third road BC. The length and the bearing of BC is 200 m and N 75° E. Find the length of AB and AC. Can anyone answer this?

Prashanth said:   3 years ago
For anticlockwise how to measure it?

MANVI said:   4 years ago
Please explain, how to calculate the angle AC?

Kripa said:   4 years ago
Then for angle AC?

Kanchan thakur said:   4 years ago
Bearing of AB=152°30'
<ABC=124°28'

Bearing of BC=?
Back bearing of AB = BA = F.B + 180 = 152°30' + 180° = 332°30'
Bearing of bc = b.b of AB+<ABC = 332°30' + 124°28' = 456°58'

This is more than 360 so;
Bearing of BC = 456°58' - 360° = 96°58'.