Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 7 (Q.No. 29)
29.
The bearing of lines OA and OB are 16° 10' and 332° 18', the value of the included angle BOA is
Discussion:
12 comments Page 2 of 2.
Pradip Pokhrel said:
1 year ago
I think for this question, we have to use the concept of a well-condition triangle for the included angle which is >30 and <120 degrees because after subtracting two bearing values comes greater than 120 degrees.
So,
Included angle = (360 - 332 10) + 16 10 = 43 52 which is >30 and <120 degree. And this includes angle.
So,
Included angle = (360 - 332 10) + 16 10 = 43 52 which is >30 and <120 degree. And this includes angle.
(1)
Sandip Ch said:
2 months ago
BB of OA = 16°10' + 180° = 196°10'.
BB of OB = 332°18' - 180° = 152°18'.
Included Angle BOA = BB of OA - BB of OB = 196°10' - 152°18' = 43°52'
Hence option D is Correct.
BB of OB = 332°18' - 180° = 152°18'.
Included Angle BOA = BB of OA - BB of OB = 196°10' - 152°18' = 43°52'
Hence option D is Correct.
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