Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 7 (Q.No. 29)
29.
The bearing of lines OA and OB are 16° 10' and 332° 18', the value of the included angle BOA is
Discussion:
11 comments Page 1 of 2.
Pradip Pokhrel said:
8 months ago
I think for this question, we have to use the concept of a well-condition triangle for the included angle which is >30 and <120 degrees because after subtracting two bearing values comes greater than 120 degrees.
So,
Included angle = (360 - 332 10) + 16 10 = 43 52 which is >30 and <120 degree. And this includes angle.
So,
Included angle = (360 - 332 10) + 16 10 = 43 52 which is >30 and <120 degree. And this includes angle.
(1)
Budheshwar Mandal said:
1 year ago
332.18 - 16.10 = 316.08.
360 - 316.08 = 43.52.
Option D is the correct Answer.
360 - 316.08 = 43.52.
Option D is the correct Answer.
(4)
Rahul said:
4 years ago
Included angle = F.B of next line - B.B of the previous line,
332°18'-(180°+16°10')= 136°8'.
332°18'-(180°+16°10')= 136°8'.
Sundeep Goudru said:
4 years ago
Bearing of the previous line - bearing of next line.
= 332-16.10= 316.08 exterior angle.
Interior angle = 360-316.08= 43.92.
Hence the nearest answer is 43.52 option D is correct.
= 332-16.10= 316.08 exterior angle.
Interior angle = 360-316.08= 43.92.
Hence the nearest answer is 43.52 option D is correct.
(5)
Teja said:
4 years ago
Correct, thanks @Soppanna Baka.
(1)
Srikanth said:
5 years ago
How @Soppanna Baka.
Explain your answer.
Explain your answer.
MUZAKKIR QURESHI said:
5 years ago
Thanks for the answer @Soppanna Baka.
Shreeraksha said:
6 years ago
Thanks all.
NILESH said:
6 years ago
The correct answer is Back bearing-Fore bearing = 136.08.
Soppanna baka said:
9 years ago
360' - 332'18" + 16'10" = 43'52"
(2)
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