# Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 7 (Q.No. 29)

29.

The bearing of lines

*OA*and*OB*are 16° 10' and 332° 18', the value of the included angle*BOA*isDiscussion:

11 comments Page 1 of 2.
Pradip Pokhrel said:
4 weeks ago

I think for this question, we have to use the concept of a well-condition triangle for the included angle which is >30 and <120 degrees because after subtracting two bearing values comes greater than 120 degrees.

So,

Included angle = (360 - 332 10) + 16 10 = 43 52 which is >30 and <120 degree. And this includes angle.

So,

Included angle = (360 - 332 10) + 16 10 = 43 52 which is >30 and <120 degree. And this includes angle.

Budheshwar Mandal said:
7 months ago

332.18 - 16.10 = 316.08.

360 - 316.08 = 43.52.

Option D is the correct Answer.

360 - 316.08 = 43.52.

Option D is the correct Answer.

(2)

Rahul said:
3 years ago

Included angle = F.B of next line - B.B of the previous line,

332°18'-(180°+16°10')= 136°8'.

332°18'-(180°+16°10')= 136°8'.

Sundeep Goudru said:
4 years ago

Bearing of the previous line - bearing of next line.

= 332-16.10= 316.08 exterior angle.

Interior angle = 360-316.08= 43.92.

Hence the nearest answer is 43.52 option D is correct.

= 332-16.10= 316.08 exterior angle.

Interior angle = 360-316.08= 43.92.

Hence the nearest answer is 43.52 option D is correct.

(4)

Teja said:
4 years ago

Correct, thanks @Soppanna Baka.

(1)

Srikanth said:
4 years ago

How @Soppanna Baka.

Explain your answer.

Explain your answer.

MUZAKKIR QURESHI said:
4 years ago

Thanks for the answer @Soppanna Baka.

Shreeraksha said:
5 years ago

Thanks all.

NILESH said:
6 years ago

The correct answer is Back bearing-Fore bearing = 136.08.

Soppanna baka said:
8 years ago

360' - 332'18" + 16'10" = 43'52"

(2)

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