Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 7 (Q.No. 29)
29.
The bearing of lines OA and OB are 16° 10' and 332° 18', the value of the included angle BOA is
316° 10'
158° 28'
348° 08'
43° 52'
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Pradip Pokhrel said:   4 weeks ago
I think for this question, we have to use the concept of a well-condition triangle for the included angle which is >30 and <120 degrees because after subtracting two bearing values comes greater than 120 degrees.

So,

Included angle = (360 - 332 10) + 16 10 = 43 52 which is >30 and <120 degree. And this includes angle.

Budheshwar Mandal said:   7 months ago
332.18 - 16.10 = 316.08.
360 - 316.08 = 43.52.
Option D is the correct Answer.
(2)

Rahul said:   3 years ago
Included angle = F.B of next line - B.B of the previous line,
332°18'-(180°+16°10')= 136°8'.

Sundeep Goudru said:   4 years ago
Bearing of the previous line - bearing of next line.
= 332-16.10= 316.08 exterior angle.
Interior angle = 360-316.08= 43.92.

Hence the nearest answer is 43.52 option D is correct.
(4)

Teja said:   4 years ago
Correct, thanks @Soppanna Baka.
(1)

Srikanth said:   4 years ago
How @Soppanna Baka.

Explain your answer.

MUZAKKIR QURESHI said:   4 years ago
Thanks for the answer @Soppanna Baka.

Shreeraksha said:   5 years ago
Thanks all.

NILESH said:   6 years ago
The correct answer is Back bearing-Fore bearing = 136.08.

Soppanna baka said:   8 years ago
360' - 332'18" + 16'10" = 43'52"
(2)


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