# Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 3 (Q.No. 19)

19.

The main plate of a transit is divided into 1080 equal divisions. 60 divisions of the vernier coincide exactly with 59 divisions of the main plate. The transit can read angles accurate upto

Discussion:

22 comments Page 1 of 3.
Sandip Mondal said:
8 months ago

We know that the total angle of the lower plate is 360 degrees.= 360 * 3600 second = 12,96,000 second.

The lower plate is divided into 1080 divisions.

So each division is =12,96,000/1080 second = 1200 second =1200".

We know the least count = d/n =( 1200"/60)= 20".

Here, d= value of the smallest division of the main scale.

n = number of divisions of Vernier scale.

The lower plate is divided into 1080 divisions.

So each division is =12,96,000/1080 second = 1200 second =1200".

We know the least count = d/n =( 1200"/60)= 20".

Here, d= value of the smallest division of the main scale.

n = number of divisions of Vernier scale.

(2)

Sourabh said:
2 years ago

All the explanations are correct assuming:

1 degree = 1hour equivalent.

So, we write 1° 00' 00"= 3600 secs.

1 degree = 1hour equivalent.

So, we write 1° 00' 00"= 3600 secs.

(1)

Arijit Khamrai said:
2 years ago

Main plate of transit =360°,divided into 1080 equal div.

So Angular value of one div= (360/1080)*60 (for min) *60 (for sec) =1200"=S.

60div of vernier coincide exacty with 59div of the main scale so, n=60.

Least count = s/n = 1200/60= 20"

So Angular value of one div= (360/1080)*60 (for min) *60 (for sec) =1200"=S.

60div of vernier coincide exacty with 59div of the main scale so, n=60.

Least count = s/n = 1200/60= 20"

(2)

Piyush said:
2 years ago

360 deg =1080*M.

M=360/1080 =0.333 deg,

M*59 =60*V,

0.333*59/60 = v,

v=0.327777.

Least count = 0.3333-0.3277 = 0.005552 deg = 19.98 sec.

M=360/1080 =0.333 deg,

M*59 =60*V,

0.333*59/60 = v,

v=0.327777.

Least count = 0.3333-0.3277 = 0.005552 deg = 19.98 sec.

(1)

MAHESH said:
2 years ago

A transit in Theodolite is such that here,

1080 divisions =360 degree.

1 div =360/1080 degrees which is S the smallest div on the main scale.

n=60.

So, LC=S/n in second gives 20".

1080 divisions =360 degree.

1 div =360/1080 degrees which is S the smallest div on the main scale.

n=60.

So, LC=S/n in second gives 20".

(1)

Vamsi Krishna said:
3 years ago

L.C of the main scale:

1080/360 = 20.

Now, L.C of vernier is;

S/V=(20*60)/60=20".

1080/360 = 20.

Now, L.C of vernier is;

S/V=(20*60)/60=20".

(2)

Longti said:
3 years ago

Thanks everyone for explaining the answer.

(1)

Ansh mishra said:
3 years ago

First of all, See the question this is telling us the main scale division 59 is equal's to 60 division of vernier it means we can understand from it is direct vernier condition((direct vernier condition (n-1)=n where as( n-1) is main scale division and (n) is division of vernier)).

So from direct vernier condition lest count will be (s/n) where (s) is the least count of the main scale and (n) is the division of the vernier.

So first we will find (s) so think that question does not have directly given but one hint is there which is 1080 division of transit means the main scale has 1080 division and we know transit is nothing but it is transit theodolite so total angle will be 360 degrees and now if we will 360/1080 then least count of the main scale can easily get but the question is ask in second not in degree.

So we will convert 360 degree into second 360*60*60 (1degree=60minutes, 1 minute=60sec)

now (360*60*60/1080)=1200 so (s)=1200.

and (n) is already given (n)=60.

Now:-

Least count = (s/n) =(1200/60) = 20.

So from direct vernier condition lest count will be (s/n) where (s) is the least count of the main scale and (n) is the division of the vernier.

So first we will find (s) so think that question does not have directly given but one hint is there which is 1080 division of transit means the main scale has 1080 division and we know transit is nothing but it is transit theodolite so total angle will be 360 degrees and now if we will 360/1080 then least count of the main scale can easily get but the question is ask in second not in degree.

So we will convert 360 degree into second 360*60*60 (1degree=60minutes, 1 minute=60sec)

now (360*60*60/1080)=1200 so (s)=1200.

and (n) is already given (n)=60.

Now:-

Least count = (s/n) =(1200/60) = 20.

(3)

Gouthami said:
3 years ago

L scale = 360/1080.

= 0.3333333*3600sec.

= 1200sec.

No. Of divisions = 59.

= 1200/59 = 20.33.

Therefore, their least count is 20".

= 0.3333333*3600sec.

= 1200sec.

No. Of divisions = 59.

= 1200/59 = 20.33.

Therefore, their least count is 20".

Krishan suthar said:
5 years ago

Here, it's 60/1080) *360.

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