Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 29)
29.
If the length of a transition curve to be introduced between a straight and a circular curve of radius 500 m is 90 m, the maximum perpendicular offset for the transition curve, is
Discussion:
14 comments Page 1 of 2.
Dilen said:
1 decade ago
How to calculate this one?
Jennie said:
1 decade ago
Any solution how to solve this?
Sanu Raja Shakya said:
10 years ago
Y = x^3/6RL.
For maximum perpendicular offset x = L = 90 m.
So Y = 90^3/6*500*90 = 2.70 m.
For maximum perpendicular offset x = L = 90 m.
So Y = 90^3/6*500*90 = 2.70 m.
Roy said:
8 years ago
Perpendicular offset from a tangent to the junction of a transition curve and a circular curve is equal = 4 times the shift.
So, P=4s=4*(L^2/24R)=L^2/6R=90^2/(6*500)=2.70m.
So, P=4s=4*(L^2/24R)=L^2/6R=90^2/(6*500)=2.70m.
Santu naskar said:
8 years ago
l^2/6R=90^2/6*500 = 2.70M.
(1)
Satla pullaiah said:
7 years ago
Can you please explain in briefly Sir?
Bhumika said:
6 years ago
Then, How to calculate deflection?
Rohit madhukarrao chormalle said:
6 years ago
Explain the answer in brief.
(1)
Manav sumara said:
5 years ago
Why you put 6?
R =24 or R =6 can anybody solve it properly?
R =24 or R =6 can anybody solve it properly?
(1)
Pkota said:
4 years ago
Shift S = L^2/24R.
Perpendicular offset = 4 x Shift=4 x (L^2/24R).
= L^2/6R.
= 90x90/6* 500 = 2.7m.
Perpendicular offset = 4 x Shift=4 x (L^2/24R).
= L^2/6R.
= 90x90/6* 500 = 2.7m.
(6)
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