Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 7)
7.
If S is the length of a subchord and R is the radius of simple curve, the angle of deflection between its tangent and sub-chord, in minutes, is equal to
Discussion:
27 comments Page 2 of 3.
Cemti said:
5 years ago
@Govarthan.
Please explain how did you get the 22/7?
Please explain how did you get the 22/7?
Sai adithya said:
7 years ago
Thanks @Sameer Sopori.
Nancy said:
7 years ago
@Sameer.
Thankyou for the explanation.
Thankyou for the explanation.
Williams said:
7 years ago
Can anyone explain the solution in detail?
Amal zaf Bannu said:
8 years ago
E is the correct answer. I agree with the given answer.
Ved prakash said:
8 years ago
Actually the angular method of curve setting ,by Rankine's deflection method the deflection angle b/w chord and point of tangency is =1720C/R i, where c is the first sub chord and R is the radius.
Daxa rathod said:
8 years ago
Give me the description of this answer.
S.venkata siva said:
1 decade ago
Give me description.
Naz said:
9 years ago
Angle of reflection = 180 * s * 60/2R degree.
= 1718.9S/R.
= 1718.9S/R.
Yamanoor said:
9 years ago
Angle of deflection=S/2R radians.
= 180 * S/2 * R degree,
= 180 * 60 * S/2 R* minutes,
= 1718.9S/R.
= 180 * S/2 * R degree,
= 180 * 60 * S/2 R* minutes,
= 1718.9S/R.
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