If S is the length of a subchord and R is the radius of simple curve, the angle of deflection between its tangent and sub-chord, in minutes, is equal to

[A].

573 S/R

[B].

573 R/S

[C].

171.9 S/R

[D].

1718.9 R/S

[E].

1718.9 S/R.

Answer: Option E

Explanation:

No answer description available for this question.

Angle of reflection = 180 * s * 60/2R degree.
= 1718.9S/R.

Gman said:
(Mar 7, 2017)

The angle of deflection = ((180/π) * s * 60)/(2 * R)°.

Daxa Rathod said:
(May 30, 2017)

Give me the description of this answer.

Ved Prakash said:
(Nov 25, 2017)

Actually the angular method of curve setting ,by Rankine's deflection method the deflection angle b/w chord and point of tangency is =1720C/R i, where c is the first sub chord and R is the radius.

Amal Zaf Bannu said:
(Dec 9, 2017)

E is the correct answer. I agree with the given answer.

Shrikant said:
(Jan 11, 2018)

Angle of deflection= (360/4π)* S/R.
This gives answer 28.64 S/R.
which is in degrees,, soo one degree is 60 min.
Thus, 28.64 S/R degrees in radians is answer E) 1718.9 S/R.

Williams said:
(Apr 15, 2018)

Can anyone explain the solution in detail?

Sameer Sopori said:
(May 1, 2018)

@Williams.

For an angle of deflection in RADIAN then use =S/2R.
For an angle of deflection in DEGREE then use =(S/2R)* (180/π),
For an angle of deflection in MINUTES then use = (S/2R)*(180/π)* 60.

Nancy said:
(Mar 6, 2019)

@Sameer.

Thankyou for the explanation.

Sai Adithya said:
(Mar 7, 2019)

Thanks @Sameer Sopori.

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