Civil Engineering - Surveying - Discussion


If S is the length of a subchord and R is the radius of simple curve, the angle of deflection between its tangent and sub-chord, in minutes, is equal to

[A]. 573 S/R
[B]. 573 R/S
[C]. 171.9 S/R
[D]. 1718.9 R/S
[E]. 1718.9 S/R.

Answer: Option E


No answer description available for this question.

S.Venkata Siva said: (Apr 22, 2015)  
Give me description.

S.Venkata Siva said: (Apr 22, 2015)  
Give me description.

Jaswant Nayal said: (Jul 30, 2015)  
Please guys give description.

Pj_Baba said: (Oct 27, 2015)  
Answer = (S/2r)*180*60/pi = 1718.87 S/R.

Josh said: (Oct 29, 2015)  
I don't think this answer (E) is correct.

It is only correct if the sub chord, S, was actually the sub arc length. Otherwise, the real answer should be sin^-1 (S/2R)*60.

Prakash Barik said: (Jan 27, 2016)  
Please give some description my friend.

Hazem said: (Mar 29, 2016)  
Yes Josh, you are completely right.

Umair said: (Aug 23, 2016)  
Yes, E is 100% correct answer.

Prem said: (Aug 24, 2016)  
Please describe the question briefly.

Abhishek Kumar said: (Sep 1, 2016)  
Please describe it clearly.

Mohammed Salahuddin Tirandaz said: (Nov 10, 2016)  
Not understanding, Please describe it clearly.

Yamanoor said: (Dec 23, 2016)  
Angle of deflection=S/2R radians.
= 180 * S/2 * R degree,
= 180 * 60 * S/2 R* minutes,
= 1718.9S/R.

Naz said: (Jan 20, 2017)  
Angle of reflection = 180 * s * 60/2R degree.
= 1718.9S/R.

Gman said: (Mar 7, 2017)  
The angle of deflection = ((180/π) * s * 60)/(2 * R)°.

Daxa Rathod said: (May 30, 2017)  
Give me the description of this answer.

Ved Prakash said: (Nov 25, 2017)  
Actually the angular method of curve setting ,by Rankine's deflection method the deflection angle b/w chord and point of tangency is =1720C/R i, where c is the first sub chord and R is the radius.

Amal Zaf Bannu said: (Dec 9, 2017)  
E is the correct answer. I agree with the given answer.

Shrikant said: (Jan 11, 2018)  
Angle of deflection= (360/4π)* S/R.
This gives answer 28.64 S/R.
which is in degrees,, soo one degree is 60 min.
Thus, 28.64 S/R degrees in radians is answer E) 1718.9 S/R.

Williams said: (Apr 15, 2018)  
Can anyone explain the solution in detail?

Sameer Sopori said: (May 1, 2018)  

For an angle of deflection in RADIAN then use =S/2R.
For an angle of deflection in DEGREE then use =(S/2R)* (180/π),
For an angle of deflection in MINUTES then use = (S/2R)*(180/π)* 60.

Nancy said: (Mar 6, 2019)  

Thankyou for the explanation.

Sai Adithya said: (Mar 7, 2019)  
Thanks @Sameer Sopori.

Govarthanan R said: (Jan 24, 2020)  
For an angle of deflection in MINUTES then use = (S/2R)*(180/π)* 60.
= S/R*((180*60)/(2*(22/7)).
=S/R *1718.18,

Cemti said: (Mar 10, 2021)  

Please explain how did you get the 22/7?

Nadeem said: (Mar 30, 2021)  
Angel of deflection in radian = S/2R.
And in radian =180 * S/2R * °.
And in minute 180 * 60 * S/2R*°.
After simplification =1718.87S/R.

Karyeija Felex said: (Jul 27, 2021)  
For all practical purposes sub chord is equal to sub arc length, so E is correct.

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