# Civil Engineering - Surveying - Discussion

### Discussion :: Surveying - Section 1 (Q.No.7)

7.

If S is the length of a subchord and R is the radius of simple curve, the angle of deflection between its tangent and sub-chord, in minutes, is equal to

 [A]. 573 S/R [B]. 573 R/S [C]. 171.9 S/R [D]. 1718.9 R/S [E]. 1718.9 S/R.

Explanation:

No answer description available for this question.

 S.Venkata Siva said: (Apr 22, 2015) Give me description.

 S.Venkata Siva said: (Apr 22, 2015) Give me description.

 Jaswant Nayal said: (Jul 30, 2015) Please guys give description.

 Pj_Baba said: (Oct 27, 2015) Answer = (S/2r)*180*60/pi = 1718.87 S/R.

 Josh said: (Oct 29, 2015) I don't think this answer (E) is correct. It is only correct if the sub chord, S, was actually the sub arc length. Otherwise, the real answer should be sin^-1 (S/2R)*60.

 Prakash Barik said: (Jan 27, 2016) Please give some description my friend.

 Hazem said: (Mar 29, 2016) Yes Josh, you are completely right.

 Umair said: (Aug 23, 2016) Yes, E is 100% correct answer.

 Prem said: (Aug 24, 2016) Please describe the question briefly.

 Abhishek Kumar said: (Sep 1, 2016) Please describe it clearly.

 Mohammed Salahuddin Tirandaz said: (Nov 10, 2016) Not understanding, Please describe it clearly.

 Yamanoor said: (Dec 23, 2016) Angle of deflection=S/2R radians. = 180 * S/2 * R degree, = 180 * 60 * S/2 R* minutes, = 1718.9S/R.

 Naz said: (Jan 20, 2017) Angle of reflection = 180 * s * 60/2R degree. = 1718.9S/R.

 Gman said: (Mar 7, 2017) The angle of deflection = ((180/π) * s * 60)/(2 * R)°.

 Daxa Rathod said: (May 30, 2017) Give me the description of this answer.

 Ved Prakash said: (Nov 25, 2017) Actually the angular method of curve setting ,by Rankine's deflection method the deflection angle b/w chord and point of tangency is =1720C/R i, where c is the first sub chord and R is the radius.

 Amal Zaf Bannu said: (Dec 9, 2017) E is the correct answer. I agree with the given answer.

 Shrikant said: (Jan 11, 2018) Angle of deflection= (360/4π)* S/R. This gives answer 28.64 S/R. which is in degrees,, soo one degree is 60 min. Thus, 28.64 S/R degrees in radians is answer E) 1718.9 S/R.

 Williams said: (Apr 15, 2018) Can anyone explain the solution in detail?

 Sameer Sopori said: (May 1, 2018) @Williams. For an angle of deflection in RADIAN then use =S/2R. For an angle of deflection in DEGREE then use =(S/2R)* (180/π), For an angle of deflection in MINUTES then use = (S/2R)*(180/π)* 60.

 Nancy said: (Mar 6, 2019) @Sameer. Thankyou for the explanation.

 Sai Adithya said: (Mar 7, 2019) Thanks @Sameer Sopori.

 Govarthanan R said: (Jan 24, 2020) For an angle of deflection in MINUTES then use = (S/2R)*(180/π)* 60. = S/R*((180*60)/(2*(22/7)). =S/R *1718.18, =1718.18S/R.