Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 7)
7.
If S is the length of a subchord and R is the radius of simple curve, the angle of deflection between its tangent and sub-chord, in minutes, is equal to
Discussion:
27 comments Page 2 of 3.
Mohammed Salahuddin Tirandaz said:
9 years ago
Not understanding, Please describe it clearly.
(1)
Yamanoor said:
9 years ago
Angle of deflection=S/2R radians.
= 180 * S/2 * R degree,
= 180 * 60 * S/2 R* minutes,
= 1718.9S/R.
= 180 * S/2 * R degree,
= 180 * 60 * S/2 R* minutes,
= 1718.9S/R.
Naz said:
9 years ago
Angle of reflection = 180 * s * 60/2R degree.
= 1718.9S/R.
= 1718.9S/R.
Gman said:
9 years ago
The angle of deflection = ((180/π) * s * 60)/(2 * R)°.
Daxa rathod said:
8 years ago
Give me the description of this answer.
Ved prakash said:
8 years ago
Actually the angular method of curve setting ,by Rankine's deflection method the deflection angle b/w chord and point of tangency is =1720C/R i, where c is the first sub chord and R is the radius.
Amal zaf Bannu said:
8 years ago
E is the correct answer. I agree with the given answer.
Shrikant said:
8 years ago
Angle of deflection= (360/4π)* S/R.
This gives answer 28.64 S/R.
which is in degrees,, soo one degree is 60 min.
Thus, 28.64 S/R degrees in radians is answer E) 1718.9 S/R.
This gives answer 28.64 S/R.
which is in degrees,, soo one degree is 60 min.
Thus, 28.64 S/R degrees in radians is answer E) 1718.9 S/R.
(1)
Williams said:
7 years ago
Can anyone explain the solution in detail?
Sameer sopori said:
7 years ago
@Williams.
For an angle of deflection in RADIAN then use =S/2R.
For an angle of deflection in DEGREE then use =(S/2R)* (180/π),
For an angle of deflection in MINUTES then use = (S/2R)*(180/π)* 60.
For an angle of deflection in RADIAN then use =S/2R.
For an angle of deflection in DEGREE then use =(S/2R)* (180/π),
For an angle of deflection in MINUTES then use = (S/2R)*(180/π)* 60.
(1)
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