Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 24)
24.
One of the tacheometric constants is additive, the other constant, is
Discussion:
7 comments Page 1 of 1.
Mayank said:
1 decade ago
D = ks+c.
Where constant c is additive having general value 0. And k is multiple having value 100.
Where constant c is additive having general value 0. And k is multiple having value 100.
(1)
Chaudhary prakash said:
8 years ago
Techeometric surveying eq
D=ks+c as solve this eq are
D=(f/I)s+(f+d)
C=f+d are additive are value a multiplicationd (f/I)
D=ks+c as solve this eq are
D=(f/I)s+(f+d)
C=f+d are additive are value a multiplicationd (f/I)
(1)
RAKESH DABHI said:
1 decade ago
D = (f/i).s+ (f+d).
Where, f/i = multiplying constant.
s = staff intercept between the bottom and top hair.
f+d = Additive constant.
D = Horizontal distance between the staff station and the observer's position.
Where, f/i = multiplying constant.
s = staff intercept between the bottom and top hair.
f+d = Additive constant.
D = Horizontal distance between the staff station and the observer's position.
Termi said:
8 years ago
I can't understand. Explain clearly.
Sanjay said:
8 years ago
Here,
D=K S+ C.
D=(f/i)s+(f+d).
Here k = (f/i) =dividing constant.
c = (f+d)=addetive constant.
D=K S+ C.
D=(f/i)s+(f+d).
Here k = (f/i) =dividing constant.
c = (f+d)=addetive constant.
Rabindra said:
7 years ago
Additive constant, C =0.
Multiplying constant, K=100.
Multiplying constant, K=100.
Sofiya said:
6 years ago
Please explain why is it 0 and 100?
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