Civil Engineering - Surveying - Discussion

18. 

Let angular value of one graduation of a tube of length x be φ seconds and R be the radius of its internal curved surface, then

[A].
[B].
[C].
[D]. .

Answer: Option A

Explanation:

No answer description available for this question.

Bestengineer said: (Sep 2, 2016)  
How? Explain.

Rajendra said: (Jan 30, 2017)  
It should be( x/R ) * 206265.

Abhishek Anand said: (Feb 11, 2017)  
Yeah,angle= (arc/radius) radians.
= (d/r) * 206265 sec.
= (206265d/r).
(1rad=206265sec).

Er Meghanada (Bhadrak) said: (Nov 17, 2017)  
x = Angular value of one graduation of tube of length.
φ = Second.
R = Radius.

D = 206265 sec.
(x/r)*d = (x/r)*206265.

φ = x/206265.

Amjad Ali said: (Feb 15, 2020)  
None of these.
Sensitivity= x*206265/R.

Raju Sarkar said: (Jun 9, 2020)  
Yes, it should be (x/R)206265.

Shiva said: (Jan 30, 2021)  
Thanks @ Er.Meghanada.

Mesbah Ullah said: (Mar 6, 2021)  
Arc = φ *R......... φ in rad.
φ rad = Arc/R.
φ = Arc/(R*rad) = x/(R*206265).

Mjm Gcek said: (Aug 13, 2021)  
Yes, you are correct @Rahendra.

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