Discussion :: Surveying - Section 2 (Q.No.18)
Let angular value of one graduation of a tube of length x be φ seconds and R be the radius of its internal curved surface, then
Answer: Option A
No answer description available for this question.
|Bestengineer said: (Sep 2, 2016)|
|Rajendra said: (Jan 30, 2017)|
|It should be( x/R ) * 206265.|
|Abhishek Anand said: (Feb 11, 2017)|
|Yeah,angle= (arc/radius) radians.
= (d/r) * 206265 sec.
|Er Meghanada (Bhadrak) said: (Nov 17, 2017)|
|x = Angular value of one graduation of tube of length.
φ = Second.
R = Radius.
D = 206265 sec.
(x/r)*d = (x/r)*206265.
φ = x/206265.
|Amjad Ali said: (Feb 15, 2020)|
|None of these.
|Raju Sarkar said: (Jun 9, 2020)|
|Yes, it should be (x/R)206265.|
|Shiva said: (Jan 30, 2021)|
|Thanks @ Er.Meghanada.|
|Mesbah Ullah said: (Mar 6, 2021)|
|Arc = φ *R......... φ in rad.
φ rad = Arc/R.
φ = Arc/(R*rad) = x/(R*206265).
|Mjm Gcek said: (Aug 13, 2021)|
|Yes, you are correct @Rahendra.|
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