Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 16)
16.
If a 30 m chain diverges through a perpendicular distance d from its correct alignment, the error in length, is
.Discussion:
21 comments Page 2 of 3.
Ravi Kumar said:
8 years ago
I can't understand please explain me.
Er Meghanada (Bhadrak ) said:
8 years ago
Formula Of Alignment correction = h Square /2L,
Length of Chain (L)= 30 m.
= h Square / 2*30 m = h Square / 60 m.
(Right Answer = d square / 60 m).
Length of Chain (L)= 30 m.
= h Square / 2*30 m = h Square / 60 m.
(Right Answer = d square / 60 m).
(1)
Sammy said:
7 years ago
For example, You are on the sloped surface and you are measuring horizontal distances, so here one end is fixed and when you move to the other end on a sloped surface, there will be the difference in elevations from two ends of the chain,
NOW, HERE WILL COME ERROR BECAUSE OF THE EARTHS CURVATURE, and that error is cumulative (an error will add with slope length). so the formula is h2/2l = d2/2*30 = d2/60 , (d= verticle distance)
NOW, HERE WILL COME ERROR BECAUSE OF THE EARTHS CURVATURE, and that error is cumulative (an error will add with slope length). so the formula is h2/2l = d2/2*30 = d2/60 , (d= verticle distance)
(3)
Anurag jain said:
7 years ago
h^2/2L is the formula of alignment correction.
= h^2/2*30.
= h^2/60.
= h^2/2*30.
= h^2/60.
(3)
Pavan said:
6 years ago
Thank you. @Anand Singh.
Goutham said:
6 years ago
Misalignment is d^2/L= d^2/30 is the right answer.
(1)
Pranay said:
6 years ago
Correction for misalignment is d^2/l.
Saad said:
6 years ago
H √2*l.
(4)
Manzoor Hussain said:
5 years ago
Thank you @Sammy.
(2)
PANKAJ PRAJAPATI said:
5 years ago
Alignment correction = h^2/2L = d^2/2 * 30 = d^2/60.
(10)
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